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Gravity and Strings

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7.2 Sources for Schwarzschild’s solution 201<br />

There are several reasons why we can expect a negative result: first of all, if the source<br />

for the Schwarzschild field were a massive point-particle, it would give rise to a timelike<br />

singularity along its worldline, but we know that the Schwarzschild singularity is spacelike.<br />

Second, the source for the gravitational field is not just mass, but any kind of energy,<br />

including the gravitational field itself. Thus, even if we have a mass distribution confined<br />

to a finite region of space (in an idealized case, a point), the gravitational field that it generates<br />

will fill the whole space <strong>and</strong> the source (mass <strong>and</strong> field) will not be confined to that<br />

region. In a sense this is already taken care of by Einstein’s equations: in our construction<br />

of the self-consistent spin-2 theory we saw that the Einstein tensor contains the “gravitational<br />

energy–momentum (pseudo)tensor” <strong>and</strong> only the matter sources are on the r.h.s. of<br />

Einstein’s equations.<br />

Anyway, we are going to check explicitly that the massive point-particle cannot be the<br />

source for the Schwarzschild metric. This calculation will prepare us for future calculations<br />

of the same kind, which, in contrast, will be successful <strong>and</strong> will help us to underst<strong>and</strong> the<br />

reason why.<br />

We consider the action for a massive particle coupled to gravity (we ignore boundary<br />

terms):<br />

S[gµν, X µ (ξ)] =<br />

c3 16πG (4)<br />

N<br />

<br />

d 4 x <br />

|g| R − Mc<br />

The equations of motion of gµν(x) <strong>and</strong> X µ (ξ) are, respectively,<br />

where<br />

Gµν(x) +<br />

8π MG(4)<br />

N c−2<br />

<br />

√<br />

|g|<br />

dξ gµρ(X)gνσ(X) ˙X ρ ˙X σ<br />

|gλτ (X) ˙X λ ˙X τ |<br />

dξ<br />

<br />

|gµν(X) ˙X µ ˙X ν |. (7.32)<br />

δ (4) [X (ξ) − x] = 0, (7.33)<br />

γ 1 2 M∇ 2 (γ )X λ + Mγ − 1 2 Ɣρσ λ ˙X ρ ˙X σ = 0, (7.34)<br />

γ = gµν(X) ˙X µ ˙X ν . (7.35)<br />

In the physical system that we are considering, the Schwarzschild gravitational field is<br />

produced by a point-particle that is at rest in the frame that we are going to use (Schwarzschild<br />

coordinates). Then, we expect the solution for X µ (ξ) to be<br />

X µ (ξ) = δ µ 0ξ. (7.36)<br />

However, the X µ equations of motion are not satisfied because the component Ɣ00 r does<br />

not vanish at the origin. Actually, it diverges, <strong>and</strong> we face here the problem of the infinite<br />

force that the gravitational field exerts over the source itself, which is similar to the infiniteself-energy<br />

problem of the classical electron mentioned at the beginning of this section.<br />

We will see that, in certain situations (in the presence of unbroken supersymmetry), this<br />

problem does not occur because the divergent gravitational field is canceled out by another<br />

divergent field (electromagnetic, scalar ...) <strong>and</strong> the equation of motion of the particle (or<br />

brane) canbe solved exactly.

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