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Gravity and Strings

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50 A perturbative introduction to general relativity<br />

Indeed, P µ Pµ is a constant: using the definition of momentum, we find, without using the<br />

equations of motion, the mass-shell condition<br />

P µ Pµ = M 2 c 2 , (3.20)<br />

<strong>and</strong> we have just shown that this constraint can be understood as a consequence of reparametrization<br />

invariance.<br />

There are two special parameters one can use. 7 One is the particle’s proper time (or<br />

length) ξ = s, defined by the property<br />

ηµν ˙X µ ˙X ν = 1. (3.21)<br />

Owing to this definition, the action is usually written as<br />

<br />

Spp[X (s)] =−Mc ds. (3.22)<br />

Although this form is unsuitable for finding the equations of motion, it tells us that the<br />

action of a massive point-particle is proportional to its worldline’s proper length, <strong>and</strong> the<br />

minimal-action principle tells us that the particle moves along worldlines of minimal proper<br />

length. Observe that, from the quantum mechanics point of view, since the measure in the<br />

path integral is the exponential of<br />

i Mc<br />

S = i<br />

<br />

<br />

ds =<br />

i<br />

−λCompton<br />

<br />

ds, (3.23)<br />

the proper length is measured in units of the particle’s reduced Compton wavelength.<br />

The second special parameter that we can use is the coordinate time ξ = X 0 = cT. This<br />

choice of gauge fixes one of the particle’s coordinates X 0 (ξ) = ξ.Inthis gauge (The physical<br />

or static gauge) one can study the non-relativistic limit ˙X i ˙X i = (v/c) 2 ≪ 1. In this limit<br />

the action (3.8) becomes, up to a total derivative, the non-relativistic action of a particle:<br />

S[X i <br />

(t)] = dt 1<br />

2 Mv2 − Mc2 . (3.24)<br />

3.1.3 The massive point-particle coupled to scalar gravity<br />

The coupling to the scalar gravitational field is dictated by the action Eq. (3.3). We compute<br />

the energy–momentum tensor using Rosenfeld’s prescription (Section 2.4.3):<br />

T µν<br />

<br />

˙X<br />

pp (x) =−Mc2 dξ<br />

µ ˙X ν<br />

δ<br />

˙X ρ ˙X σ<br />

(d) [X (ξ) − x], (3.25)<br />

ηρσ<br />

which is conserved, as one can prove by using the equations of motion. The trace is identical<br />

to the Lagrangian, 8 <strong>and</strong> thus the action for the coupled particle-plus-gravity system<br />

7 Purists call the same curve with two different parametrizations different curves, but from a physical point of<br />

view they are clearly the same object.<br />

8 Observe that, in the static gauge, the 00 component of this tensor gives Eq. (3.6).

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