04.06.2013 Views

Gravity and Strings

Gravity and Strings

Gravity and Strings

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

11.2 KK dimensional reduction on a circle S 1 307<br />

because that would spoil U(1) gauge invariance. The scalar acts as a sort of local coupling<br />

constant. In particular, its presence modifies the mass of the particle, which is no longer the<br />

coefficient in front of the action: if the metric is asymptotically flat <strong>and</strong> K0 is the constant<br />

value at infinity of K , then the mass is the coefficient in front of the action times K0. We<br />

have already taken this into account in writing Eq. (11.66).<br />

KK modes <strong>and</strong> also string-theory objects called “winding modes” <strong>and</strong> “D0-branes” that<br />

we will study are examples of “K particles.” The former couple to the inverse of the KK<br />

scalar, i.e. K = k−1 ,asweare immediately going to see. Winding modes couple to k directly,<br />

K = k, <strong>and</strong> D0-branes couple to the dilaton e−φ in string theory.<br />

Although we are going to explain this procedure (called direct dimensional reduction)<br />

in full detail, it is worth stressing that we are not going to prove that the two actions are<br />

completely equivalent. Rather, what we are going to prove is that all the solutions of the<br />

first action are of the form of those of the second one for some value of the mass <strong>and</strong> charge.<br />

If we take only one specific value of the mass <strong>and</strong> charge, we are reducing the system to<br />

some sector with a given, fixed, momentum in the internal direction.<br />

Our starting point is the action of a point-like massless particle given in Eq. (3.258),<br />

which we rewrite here for convenience:<br />

ˆS[ ˆX ˆµ (ξ), γ (ξ)] =− p<br />

2<br />

<br />

dξ γ − 1 2 ˆg ˆµˆν( ˆX) ˙ ˆX ˆµ ˙ ˆX ˆν . (11.68)<br />

This action is usually said to be invariant under GCTs. In fact it is just covariant, since<br />

one goes from one metric to a different (even if physically equivalent) one. This happens<br />

typically when the action depends on potentials instead of field strengths. The infinitesimal<br />

transformations giving ˜δS = 0 are<br />

˜δ ˆX ˆµ = ˆX ′ˆµ − ˆX ˆµ =ˆɛ ˆµ ( ˆX),<br />

˜δ ˆg ˆµˆν =ˆg ′<br />

ˆµˆν ( ˆX ′ ) −ˆg ˆµˆν( ˆX) =−2 ˆgˆλ( ˆµ ∂ˆν)ˆɛ ˆλ .<br />

Let us now consider infinitesimal displacements in the direction ˆɛ ˆµ ,<br />

δˆɛ ˆX ˆµ =ˆɛ ˆµ ,<br />

δˆɛ ˆg ˆµˆν =ˆg ˆµˆν( ˆX ′ ) −ˆg ˆµˆν( ˆX) =ˆɛ ˆλ ∂ˆλ ˆg ˆµˆν.<br />

Using the formulae in Chapter 1, we find that the change of the action is now<br />

δˆɛ ˆS =− p<br />

<br />

2<br />

(11.69)<br />

(11.70)<br />

dξγ − 1 <br />

2 Lˆɛ ˆg<br />

˙ˆX ˆµˆν<br />

ˆµ ˙ˆX ˆν . (11.71)<br />

Thus, the action is invariant if <strong>and</strong> only if ˆɛ ˆµ =ˆɛ ˆk ˆµ , ˆɛ being an infinitesimal constant<br />

parameter <strong>and</strong> ˆk ˆµ being a Killing vector. In other words, if the metric admits an isometry,<br />

the above action is invariant under the above symmetry <strong>and</strong> there is a conserved quantity,<br />

namely the momentum in the ˆk ˆµ direction:<br />

ˆP =−pγ − 1 2 ˆk ˆµ ˆX ˆµ ,<br />

˙ ˆP = 0. (11.72)

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!