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Gravity and Strings

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118 Action principles for gravity<br />

where hµν = gµν − n2nµnν is the induced metric on the hypersurface ∂M (see Section 1.8).<br />

Thus, we arrive at<br />

<br />

δSEH = − d d x |g| G µν δgµν + (−1) d−1<br />

<br />

M<br />

− (−1) d−1<br />

<br />

∂M<br />

d<br />

∂M<br />

d−1 n µ h σν ∇µδgσν<br />

d d−1 n µ h σν ∇σ δgµν. (4.21)<br />

This is the final form of the variation of the action we were after. Now, we would like to be<br />

able to obtain the Einstein equation by requiring the action to be stationary (so δSEH = 0)<br />

under arbitrary variations of the metric vanishing on the boundary:<br />

<br />

= 0. (4.22)<br />

∂M<br />

δgµν<br />

If δgµν is constant on the boundary, then its covariant derivative projected onto the boundary<br />

directions with h µν must vanish:<br />

h σν ∇σ δgµν = 0, (4.23)<br />

<strong>and</strong> the second of the two boundary terms vanishes. However, the first does not vanish<br />

unless we impose boundary conditions for the covariant derivative of the variation of the<br />

metric. In order to obtain the Einstein equation we must cancel out that boundary term with<br />

the variation of another boundary term added to the Einstein–Hilbert action. This boundary<br />

term is nothing but the integral over the boundary of the trace of the extrinsic curvature of<br />

the boundary given in Eq. (1.149). Observe that<br />

δK = δh µ ν∇µn ν + h µ νδƔµρ ν n ρ . (4.24)<br />

The first term vanishes on the boundary due to our boundary condition (4.22). Using<br />

Eq. (3.282) for δƔ, wefind<br />

δK| ∂M = 1<br />

2 nρ h µσ ∇ρδgµσ . (4.25)<br />

In conclusion, the action that one should use is the following [436, 932]:<br />

SEH[g] = 1<br />

χ 2<br />

<br />

d<br />

M<br />

dx √ d 2<br />

|g| R + (−1)<br />

χ 2<br />

<br />

d<br />

∂M<br />

d−1 K. (4.26)<br />

Under otherwise arbitrary variations of the metric satisfying Eq. (4.22), we have shown<br />

that the variation of the Einstein–Hilbert action with boundary term (4.26), is just<br />

δSEH =− 1<br />

χ 2<br />

<br />

d<br />

M<br />

d x |g| G µν δgµν, (4.27)<br />

<strong>and</strong> then the vacuum Einstein equation follows, as we wanted.

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