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Gravity and Strings

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3.2 <strong>Gravity</strong> as a self-consistent massless spin-2 SRFT 81<br />

term as a redefinition of the canonical energy–momentum tensor. This redefinition is, however,<br />

important. On the one h<strong>and</strong>, the equations of motion are going to be corrected <strong>and</strong><br />

therefore the addition of terms vanishing on-shell to first order is going to become meaningful<br />

at higher orders <strong>and</strong> should be considered with care. On the other h<strong>and</strong>, if we obtain<br />

an action that is invariant under the above gauge symmetry, the equations of motion are<br />

going to satisfy a gauge identity that is, at the same time, the condition for the invariance<br />

of the action. By varying directly the Lagrangian Eq. (3.178) under δ (1)<br />

ɛ ,wefind that it will<br />

be invariant up to O(χ 2 ) if the gravitational energy–momentum tensor that appears in the<br />

equations of motion (3.171) satisfies, to first order in χ,<br />

∂µt (0)µ (0)µ<br />

σ (h) = ∂µ t can σ (h) + Dµ ρ(h)h ρ <br />

σ . (3.185)<br />

On taking explicitly the derivative on the r.h.s., we obtain the gauge identities 34 associated<br />

with invariance under δ (1)<br />

ɛ :<br />

∂µt (0)µ σ (h) = γνρσ D νρ (h), γνρσ = 1<br />

<br />

∂νhρσ + ∂ρhνσ − ∂σ hνρ , (3.186)<br />

2<br />

Thus, if we look for invariance under the gauge transformations δ (1)<br />

ɛ , the gravitational<br />

energy–momentum tensor that we will put on the r.h.s. of Eq. (3.171) has to be of the<br />

form<br />

t (0) µσ (h) = t (0)<br />

can µσ (h) + Dµ ρ(h)h ρ σ + ∂ρ ρ µσ , (3.187)<br />

but wecan no longer add on-shell-vanishing terms proportional to D µ ρ(h) because then<br />

the above gauge identities would not be satisfied. Here we see how the requirement of<br />

gauge symmetry constrains the possible energy–momentum tensors. Comparing this situation<br />

with our construction of the scalar theory of gravity in which the energy–momentum<br />

tensor could be asymmetric <strong>and</strong> did not have to satisfy any kind of conditions, we are much<br />

better off.<br />

Still, the redefined canonical energy–momentum tensor<br />

t (0)<br />

can µσ (h) + Dµ ρ(h)h ρ σ<br />

is not symmetric as we had hoped <strong>and</strong> we have to find additional terms ∂ρ ρ µσ that cancel<br />

out exactly the antisymmetric part of our energy–momentum tensors. There is only one<br />

systematic procedure for doing this <strong>and</strong> only for the canonical one: the Belinfante method<br />

explained in Chapter 2 which, unfortunately, requires the addition of on-shell-vanishing<br />

terms. Let us, nevertheless, see where we are taken by this method. It is straightforward<br />

(but long <strong>and</strong> tedious) to find<br />

ρµ σ =−2∂ [ρ h µ] βh β σ − 2∂βh [ρ σ h µ]β + ∂ [ρ hh µ] σ + ησ [ρ ∂βhh µ]β . (3.188)<br />

The antisymmetric part of the modified canonical tensor t (0)<br />

can µσ + ∂ρ ρ µσ is −Dρ[µh ρ σ ],<br />

34 We are using the zeroth-order gauge identity ∂µD µν (h) = 0, which is, obviously, valid.

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