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Gravity and Strings

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8.2 The Einstein–Maxwell system 219<br />

where E = (E1, E2, E3) <strong>and</strong> B = (B1, B2, B3) are the electric <strong>and</strong> magnetic 3-vector fields<br />

in that coordinate system, <strong>and</strong>, thus, with ∇ =(∂1,∂2,∂3)<br />

<br />

Ei = F0i,<br />

Bi =− 1<br />

2ɛijkFkl, ⇔<br />

⎧<br />

⎪⎨ E =−∇φ −<br />

⎪⎩<br />

1 ∂<br />

c ∂t A,<br />

(8.18)<br />

B = ∇ × A.<br />

The field strength (<strong>and</strong> the action) is invariant under the Abelian gauge transformations<br />

A ′ µ = Aµ + ∂µ (8.19)<br />

with smooth, gauge parameter . Depending on which gauge group we consider (R or<br />

U(1)), must be a single-valued or multivalued function. 6 In differential-forms language<br />

A = Aµdx µ , A ′ = A + d, F = 1<br />

2 Fµνdx µ ∧ dx ν = dA, (8.20)<br />

<strong>and</strong> the gauge invariance of F is a consequence of d 2 = 0. Using these differential forms,<br />

the Maxwell action can be rewritten as follows:<br />

SM[A] = 1<br />

<br />

F ∧<br />

8c<br />

⋆ F. (8.21)<br />

Observe that there is no matter charged with respect to Aµ in this system. This is analogous<br />

to the presence of no matter fields in the Einstein–Hilbert action. However, the<br />

Einstein–Hilbert action contains the self-coupling of gravity <strong>and</strong> therefore the presence<br />

of a coupling constant in it makes sense, whereas in the Maxwell theory there are no direct<br />

interactions between photons <strong>and</strong>, in principle, there is neither an electromagnetic coupling<br />

constant nor a unit of electric charge. We will see that things are a bit more complicated in<br />

the presence of gravity, through which photons do interact.<br />

The equations of motion of gµν <strong>and</strong> Aµ are<br />

Gµν − 8πG(4)<br />

N<br />

c4 Tµν = 0, (8.22)<br />

∇µF µν = 0 (Maxwell’s equation), (8.23)<br />

where<br />

Tµν = −2c δSM[A]<br />

√<br />

|g| δg µν = Fµρ Fν ρ − 1<br />

4 gµν F 2<br />

(8.24)<br />

is the energy–momentum tensor of the vector field, which is traceless7 in d = 4. The<br />

tracelessness of the electromagnetic energy–momentum tensor implies that R = 0 <strong>and</strong> the<br />

6 If the gauge group is R, the elements of the group will be e/L , whereas, if it is U(1), they will be ei/L ,<br />

where L is a constant introduced to make the exponent dimensionless because is dimensionful. In the<br />

second case will have to be identified with + 2π L. When there is a unit of charge, L is related to it.<br />

7 This property is associated with the invariance of the Maxwell Lagrangian in curved spacetime under Weyl<br />

rescalings of the metric,<br />

g ′ µν = 2 (x)gµν. (8.25)<br />

In fact, if = e σ , then for infinitesimal transformations δσ gµν = 2σ(x)gµν we have<br />

δσ SM = δSM<br />

δσ gµν ∼ σ T<br />

δgµν<br />

µν gµν = 0. (8.26)

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