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Gravity and Strings

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646 Appendix F<br />

The non-vanishing components of the Ricci tensor are<br />

Rtt = R (δ)<br />

tt − 1<br />

Rin jm =−1<br />

2 δijδnm<br />

Rρρ = R (δ) 1 N ρρ + 2 n=1 rn(µf(n)) − 1 2<br />

Rqr = R (δ)<br />

qr<br />

4 µ N n=1 rn(ln fn) ′ λ ′ ,<br />

<br />

∇2 <br />

fn + µf(n) (ln fn) ′2 <br />

,<br />

<br />

(µf(n)) 1 <br />

′<br />

′<br />

2 ln f(n) ,<br />

N<br />

rn(ln fn) ′ ,<br />

− 1<br />

2 gqrµ(ln R) ′<br />

n=1<br />

(F.43)<br />

where we have indicated with the superscript (δ) the components of the curvature of the<br />

δ-dimensional metric that one obtains if the coordinates yn are suppressed.<br />

The Ricci scalar is<br />

R = R (δ) + 1<br />

2<br />

N<br />

n=1<br />

d-dimensional metrics of the general form<br />

rn<br />

<br />

∇ 2 (δ) ln f(n) + f −1<br />

(n) ∇2 f(n) + µ (ln f(n)) ′ 2 <br />

. (F.44)<br />

F.2.4 A general metric for extreme p-branes<br />

ds 2 = H 2x ηijdy i dy j + H −2y ηmndx m dx n , (F.45)<br />

where i, j = 0, 1,...,p <strong>and</strong> m, n = p + 1,...,d − 1 <strong>and</strong> H is a function solely of the<br />

x m s often occur in the study of p-branes. The coordinates y i correspond to the p-brane<br />

worldvolume <strong>and</strong> the coordinates x m are transverse to the p-brane. Observe that, with our<br />

conventions, ηmn =−δmn. The non-vanishing components of the Levi-Cività connection<br />

are<br />

Ɣi j m = xηijH 2(x+y)−1 ∂m H, Ɣim j = xδi j H −1 ∂m H,<br />

Ɣmn p =−yH −1<br />

<br />

δpm∂n H + δpn∂m H − δmn∂p H<br />

The non-vanishing components of the Ricci tensor are<br />

Ri j = gi j∇ 2 ln H x ,<br />

Rmn = gmn∇ 2 ln H −y + zH −1 ∂m∂n H<br />

<br />

.<br />

+ H −2 ∂m H∂n H x 2 (p + 1) + y 2 ( ˜p + 1) + (2y − 1)z ,<br />

(F.46)<br />

(F.47)<br />

where we have used the fact that<br />

|g|=H z−2y , z = x(p + 1) − y( ˜p + 1), (F.48)<br />

<strong>and</strong> the fact that, for a scalar function of the x m sinthis metric,<br />

∇ 2 f (x m ) =−H 2y−1 z∂m H∂m f + H∂ 2 f , ∂ 2 ≡+∂m∂m,<br />

∇ 2 ln H = (1 − z)H 2y−2 (∂ H) 2 − H 2y−1 ∂ 2 H.<br />

(F.49)

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