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Starting electronics<br />

Alternatively, we may define the farad (as we promised we<br />

would, earlier in the chapter) as being the capacitance which<br />

will store a charge of one coulomb when a voltage of one volt<br />

is applied.<br />

We can now understand why it is that changing the capacitor<br />

value changes the time constant, and hence changes the<br />

associated time delay in the changing voltage across the capacitor.<br />

Increasing the capacitance, say, increases the charge<br />

stored. As the current flowing is determined by the resistance<br />

in the circuit, and is thus fixed at any particular voltage, this<br />

increased charge takes longer to build up or longer to decay<br />

away. Reducing the capacitance reduces the charge, which is<br />

therefore more quickly stored or more quickly discharged.<br />

Similarly, as the resistor in the circuit defines the current<br />

flowing to charge or discharge the capacitor, increasing or<br />

decreasing its value must decrease or increase the current,<br />

therefore increasing or decreasing the time taken to charge or<br />

discharge the capacitor. This is why the circuit’s time constant<br />

is a product of both capacitance and resistance values.<br />

Capacitance values<br />

Finally, we can look at how the size and construction of<br />

capacitors affects their capacitance. The capacitance of a<br />

basic capacitor for example, consisting of two parallel, flat<br />

plates separated by a dielectric may be calculated from the<br />

formula:<br />

96

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