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Starting electronics<br />

So, the frequency of the output signal of the circuit of Figure<br />

5.2 is:<br />

or, more correctly speaking:<br />

Equation 1 is quite important really, because it shows that<br />

the frequency of the signal is inversely proportional to the<br />

capacitance. If we decrease the value of the capacitor we will<br />

increase the frequency. We can test this by taking out the<br />

10 µF capacitor and putting in a 1 µF capacitor. Now, the LED<br />

flashes so quickly (about 58 times a second) that your eye<br />

can’t even detect it is flashing and it appears to be always on.<br />

If you replace the capacitor with one of a value of say 100 µF<br />

the LED will flash only very slowly.<br />

Now, let’s stop and think about what we’ve just done. Basically<br />

we’ve used a capacitor in precisely the ways we looked<br />

at last chapter — to charge and discharge with electrical<br />

energy so that the voltage across the capacitor goes up and<br />

down at the same time. True, in the experiments last chapter<br />

you were the switch, whereas this chapter an IC has taken<br />

your place. But the principle — charging and discharging a<br />

capacitor — is the same.<br />

The current which enters the capacitor to charge it, then<br />

leaves the capacitor to discharge it, is direct current because<br />

it comes from a 9 V d.c. battery. However, if we look at the<br />

110

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