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Starting electronics<br />

can calculate each voltage as being a function of the battery<br />

voltage, given by:<br />

and<br />

Now, we know that the voltage across the diode can only<br />

vary between about 0 V and 0V8 (given by the characteristic<br />

curve), but there’s nothing to stop us hypothesising about<br />

larger voltages than this, and drawing up a table of voltages<br />

which would thus occur across the resistor. Table 7.1 is such<br />

a table, but it takes the process one stage further by calculating<br />

the hypothetical current through the resistor at these<br />

hypothetical voltages.<br />

From Table 7.1 we can now plot a second curve on the diode<br />

characteristic curve, of diode voltage against resistor current.<br />

Figure 7.6 shows the completed characteristic curve (labelled<br />

Load line R=60R). The curve is actually a straight line — fairly<br />

obvious, if you think about it, because all we’ve done is plot a<br />

voltage and a current for a resistor, and resistors are ohmic<br />

and linear. Because in such a circuit as that of Figure 7.4 the<br />

resistor is known as a load i.e. it absorbs electrical power, the<br />

line on the characteristic curve representing diode voltage<br />

and resistor current is called the load line.<br />

Where the load line and the characteristic curve cross is<br />

the operating point. As its name implies, this is the point<br />

representing the current through and voltage across the<br />

components in the circuit. In this example the diode voltage<br />

is thus 1 V and the diode current is 33 mA at the operating<br />

point.<br />

152

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