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[Studies in Computational Intelligence 481] Artur Babiarz, Robert Bieda, Karol Jędrasiak, Aleksander Nawrat (auth.), Aleksander Nawrat, Zygmunt Kuś (eds.) - Vision Based Systemsfor UAV Applications (2013, Sprin

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314 A. Czornik, A. <strong>Nawrat</strong>, and M. Niezabitowski<br />

and therefore<br />

∣<br />

∣‖x(p + 1)‖ 2 −‖x(p)‖ 2∣ ∣ 1<br />

≤<br />

4<br />

1<br />

2<br />

1<br />

2<br />

s<br />

∑<br />

i, j,k=1<br />

(<br />

s s<br />

∑ x j(p)) 2 ∑<br />

j=1<br />

s<br />

∑<br />

i, j,k=1<br />

∣<br />

∣a (i)<br />

∣ ∣∣<br />

jk (p)+a(i) kj (p) (<br />

x<br />

2<br />

j (p)+x 2 k (p)) ≤<br />

(∣ ∣ )<br />

∣∣a (i)<br />

∣∣x<br />

jk (p)+a(i) kj (p) 2<br />

j (p) ≤<br />

∣<br />

∣a (i)<br />

i, j,k=1<br />

∣ ∣∣<br />

jk (p)+a(i) kj (p) = ‖x(p)‖ 2 b(p).<br />

Now, for natural p = 0,...,n the follow<strong>in</strong>g <strong>in</strong>equality<br />

−‖x(p)‖ 2 b(p) ≤‖x(p + 1)‖ 2 −‖x(p)‖ 2 ≤‖x(p)‖ 2 b(p)<br />

holds.<br />

Divid<strong>in</strong>g the last <strong>in</strong>equality by ‖x(p)‖ 2 we obta<strong>in</strong><br />

and therefore<br />

n<br />

∏<br />

p=0<br />

−b(p) ≤<br />

(1 − b(p)) ≤<br />

‖x(p + 1)‖2<br />

‖x(p)‖ 2<br />

‖x(n + 1)‖2<br />

‖x(0)‖ 2<br />

− 1 ≤ b(p),<br />

≤<br />

n<br />

∏<br />

p=0<br />

(1 + b(p))<br />

F<strong>in</strong>ally, multiply<strong>in</strong>g the last <strong>in</strong>equality by ‖x(0)‖ 2 , our upper (7) and lower (8) estimates<br />

follow immediately what ends the proof.<br />

The next four examples illustrate our estimates.<br />

Example 1. Consider system (1) with (A(n)) n∈N given by<br />

Namely, its elements are as follows<br />

[ √<br />

2s<strong>in</strong>n<br />

1<br />

A(n)= √n 3 +10<br />

]. 2cosn<br />

1<br />

n 2 +20<br />

a 11 (n)= √ 2s<strong>in</strong>n a 12 (n)= 1<br />

n 3 +10<br />

a 21 (n)= 1 a<br />

n 2 +20 22 (n)= √ 2cosn .<br />

Apply<strong>in</strong>g the above-mentioned elements of (A(n)) n∈N to (3) and (4) we obta<strong>in</strong> (5)<br />

<strong>in</strong> the follow<strong>in</strong>g form

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