epdf.pub_cbest-cliffs-test-prep13a9b242c7cb4125e6cca92d00a73d5a41681

Answers and Complete Explanations for Practice Test 1
25. D. The state requires no more than 50% asphalt. So 50% of 200 square feet is 100 square
feet of asphalt maximum. Notice that this maximum limit eliminates choices A and E. The
other requirement is no less than 20% grass. So 20% of 200 is 40 square feet of grass as a
minimum. This eliminates choices B and C. Only choice D provides no more than 50%
asphalt and no less than 20% grass.
26. C. The selling price for 1 dozen at 3 for $.85 is 3# 4= 12=1 dozen = $ . 85 # 4 = $ 3.
40.
Hence, 6 dozen will yield $ 3. 40 # 6 = $ 20.
40. The cost for 6 dozen at $1.80 per dozen is
$ 1. 80 # 6 = $ 10.
80. Hence, the profit on 6 dozen of these items will be $ 20. 40 - $ 10.
80,
or $9.60.
27. E. Since his scores were all between 72% and 94%, Arnold’s average for the 8 tests must
fall between the highest and lowest scores. The average for all 8 tests, however, does not
necessarily have to be 83%, the average of only the highest and lowest scores.
28. D. Price today = $100
In 1 year = $100 + 10%
of $ 100 = $ 110
In 2 years = $110 = 10%
of $ 110 = $ 121
In 3 years = $121 + 10%
of $ 121 = $ 133.
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29. A. To change centigrade degrees to Fahrenheit degrees, simply plug into the formula and
solve:
F° = 9 ⁄5 C + 32°
F° = 9 ⁄5 (25°) + 32°
F° = 45° + 32°
F° = 77°
30. D. Volume equals length # width # height, or 25cm # 10cm # 8cm
= 2,
000 cc. Since 2,000
milliliters of water equals 2,000 cc of space, exactly 2 liters are needed (since 1 liter =
1,000 milliliters).
31. B. To find the answer, add 49 3 ⁄5 and 7 1 ⁄2.
49 3 ⁄5 = 49 6 ⁄10
7 1 ⁄2 = 7 5 ⁄10
56 11 ⁄10 = 57 1 ⁄10
The total amount of fabric purchased was 57 1 ⁄10 yards.
Note: The 3 1 ⁄2 square yards given in the original information is not needed to find the
answer.
32. C. To solve an addition problem containing fractions with different denominators, a common
denominator must be found. Both 90 (choice A) and 30 (choice C) are common denominators,
but only 30 is the lowest common denominator. Using 30 for the denominator
eliminates the necessity of reducing your final answer and also minimizes the size of the
numbers in your computations.
33. A. There are 36 possible combinations of two dice. Of these 36 combinations, only 6
combinations equal 7 (1,6; 2,5; 3,4; 4,3; 5,2; 6,1). Thus, 6 out of 36 equals 6 ⁄36, or 1 ⁄6.
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