12.07.2015 Views

format .pdf, 0.9 MB - Recreaţii Matematice

format .pdf, 0.9 MB - Recreaţii Matematice

format .pdf, 0.9 MB - Recreaţii Matematice

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

⎛⎞⎛⎞λ 1 0 ... 0m 11 m 12 ... m 1nFie D = ⎜ 0 λ 2 ... 0⎟⎝... ... ... ... ⎠ ,cuλ i 6= 0, i = 1,n, M = ⎜ 0 m 22 ... m 2n⎟⎝ ... ... ... ... ⎠ ,0 0 ... λ n 0 0 ... m nnm ii 6=0, i = 1,n şi M ij complementul algebric al lui m ij în matricea M. Notăm cud =detM 6= 0.Relaţia dată esteechivalentăcuDM −1 = t MD. Deoarece⎛⎞ ⎛⎞λ 1 0 ... 0 M 11 M 21 ... M n1DM −1 = 1 ⎜ 0 λ 2 ... 0⎟ ⎜ 0 M 22 ... M n2⎟d ⎝... ... ... ... ⎠ ⎝ ... ... ... ... ⎠ =0 0 ... λ n 0 0 ... M nn⎛⎞λ 1 M 11 λ 1 M 21 ... λ 1 M n1= 1 ⎜ 0 λ 2 M 22 ... λ 2 M n2⎟d ⎝ ... ... ... ... ⎠ şi0 0 ... λ n M nn⎛⎞ ⎛⎞m 11 0 ... 0 λ 1 0 ... 0t MD = ⎜m 12 m 22 ... 0⎟ ⎜ 0 λ 2 ... 0⎟⎝ ... ... ... ... ⎠ ⎝... ... ... ... ⎠ =m 1n m 2n ... m nn 0 0 ... λ n⎛⎞λ 1 m 11 0 ... 0= ⎜λ 1 m 12 λ 2 m 22 ... 0⎟⎝ ... ... ... ... ⎠λ 1 m 1n λ 2 m 2n ... λ n m nnrezultă că m ij =0, oricare ar fi i

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!