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Leonhard EULER

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12<br />

1. MILNÍKY MATEMATIKY PŘED <strong>EULER</strong>EM<br />

n<br />

V(n) = ∑<br />

k=<br />

1<br />

n<br />

∆V k = π h ∑<br />

k=<br />

1<br />

r 2 (kh).<br />

U koule o poloměru a je podle Pythagorovy věty r 2 (z) = a 2 – z 2 , tedy pro z = kh je dolní<br />

odhad objemu koule (symetrie osy z vzhledem k počátku 0)<br />

n<br />

V(n) = 2 π h ∑<br />

k=<br />

1<br />

(a 2 – k 2 h 2 ) = 2 π n<br />

a (na 2 –<br />

a<br />

n<br />

2<br />

2<br />

n<br />

∑<br />

k=<br />

1<br />

k 2 ) = 2 π a 3 (1 –<br />

1<br />

3<br />

n<br />

n<br />

∑<br />

k=<br />

1<br />

k 2 ) .<br />

Obr. 1.8 – Dvě rotační tělesa.<br />

n<br />

Protože ∑<br />

k=<br />

1<br />

k 2 = 6<br />

n (n+1)(2n+1) (poznámka dále), je<br />

V(n) =2 π a 3 1 n<br />

(1 –<br />

3 (n+1)(2n+1)) = 2 π a 3 1 1 1<br />

(1 – (1+ )(2+ )) .<br />

n 6<br />

6 n n<br />

Když nyní poroste n do nekonečna a tloušťka vrstviček h bude konvergovat k 0, bude<br />

V = 2πa 3 lim n→∞ (1 – 6<br />

1 (1+ n<br />

1 )(2+ n<br />

1 )) = 2 π a<br />

3<br />

(1 – 6<br />

1<br />

limn→∞ (1+ n<br />

1 )(2+ n<br />

1 )) = 3<br />

4 π a 3 .<br />

Obr. 1.9 – Koule vepsaná do válce. Boční pohled.<br />

F. KOUTNÝ: <strong>Leonhard</strong> <strong>EULER</strong>

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