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定 标 算 法 —— 步 骤 二2. 求 解 t3, f, k1k1=0 作 为 初 始 值 , 则 :x−uc=u−ucy−vc=v−vcfs(r1 X + r2Y+ r3Z + t1)x =+r X + rY + r Z + t778f ( r4 X + rY5+ r6Z + t2)y =+r X + rY + r Z + t89933uv00