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Nonlinear Fiber Optics - 4 ed. Agrawal

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190 Chapter 6. Polarization Effects<br />

time derivatives can be set to zero in the quasi-CW case. If we also neglect fiber losses,<br />

Eqs. (6.1.15) and (6.1.16) r<strong>ed</strong>uce to<br />

dA +<br />

dz<br />

dA −<br />

dz<br />

= iΔβ<br />

2 A − + 2iγ<br />

3 (|A +| 2 + 2|A − | 2 )A + , (6.3.1)<br />

= iΔβ<br />

2 A + + 2iγ<br />

3 (|A −| 2 + 2|A + | 2 )A − . (6.3.2)<br />

Consider first the low-power case and neglect the nonlinear effects (γ = 0). The<br />

resulting linear equations are easily solv<strong>ed</strong>. As an example, when the input beam with<br />

power P 0 is σ + -polariz<strong>ed</strong>, the solution is given by<br />

A + (z)= √ P 0 cos(πz/L B ), A − (z)=i √ P 0 sin(πz/L B ), (6.3.3)<br />

where the beat length L B = 2π/(Δβ). The state of polarization is generally elliptical<br />

and evolves periodically with a period equal to the beat length. The ellipticity and the<br />

azimuth of the polarization ellipse at any point along the fiber can be obtain<strong>ed</strong> using<br />

e p = |A +|−|A − |<br />

|A + | + |A − | , θ = 1 ( )<br />

A+<br />

2 tan−1 . (6.3.4)<br />

A −<br />

Equations (6.3.1) and (6.3.2) can be solv<strong>ed</strong> analytically even when nonlinear effects<br />

become important. For this purpose, we use<br />

( ) 3Δβ 1/2<br />

√<br />

A ± =<br />

p± exp(iφ ± ), (6.3.5)<br />

2γ<br />

and obtain the following three equations satisfi<strong>ed</strong> by the normaliz<strong>ed</strong> powers p + and p −<br />

and the phase difference ψ ≡ φ + − φ − :<br />

dp +<br />

dZ = √ 2p + p − sinψ, (6.3.6)<br />

dp −<br />

dZ = −√ 2p + p − sinψ, (6.3.7)<br />

dψ<br />

dZ = p − − p +<br />

√ cosψ + 2(p − − p + ),<br />

p+ p −<br />

(6.3.8)<br />

where Z =(Δβ)z/2. These equations have the following two quantities that remain<br />

constant along the fiber [45]:<br />

p = p + + p − , Γ = √ p + p − cosψ + p + p − . (6.3.9)<br />

Note that p is relat<strong>ed</strong> to the total power P 0 launch<strong>ed</strong> into the fiber through p = P 0 /P cr ,<br />

where P cr is obtain<strong>ed</strong> from Eq. (6.3.5) and is given by<br />

P cr = 3|Δβ|/(2γ). (6.3.10)<br />

Because of the two constants of motion, Eqs. (6.3.6)–(6.3.8) can be solv<strong>ed</strong> analytically<br />

in terms of the elliptic functions. The solution for p + is [34]<br />

p + (z)= 1 2 p − √ m|q| cn(x), (6.3.11)

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