29.03.2016 Views

Nonlinear Fiber Optics - 4 ed. Agrawal

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

316 Chapter 8. Stimulat<strong>ed</strong> Raman Scattering<br />

such that ∫ ∞<br />

0 h j(t) =1 for j = a and b. Physically, h a and h b represent the isotropic<br />

and anisotropic parts of the nuclear response with the relative strengths f a and f b ,<br />

respectively.<br />

The tensor nature of χ (3) plays an important role in Eq. (8.5.1). For silica fibers,<br />

the third-order susceptibility has the form given in Eq. (6.1.2). Using it in Eq. (8.5.1)<br />

together with Eq. (8.5.2), the product χ (3)<br />

ijklR(t) can be written as [5]:<br />

[<br />

χ (3)<br />

1 − fR<br />

ijklR(t) =χ(3) xxxx (δ ij δ kl + δ ik δ jl + δ il δ jk )<br />

3<br />

]<br />

+ f a h a (t)δ ij δ kl + 1 2 f bh b (t)(δ ik δ jl + δ il δ jk ) , (8.5.3)<br />

where the three components of χ (3)<br />

ijkl<br />

appearing in Eq. (6.1.2) were taken to be equal in<br />

magnitude.<br />

In the case of SRS, we should consider the pump and Stokes fields separately. We<br />

follow the treatment of Section 7.6.1 and write the total electric field E and induc<strong>ed</strong><br />

polarization P NL in the form<br />

E(t) =Re[E p exp(−iω p t)+E s exp(−iω s t)], (8.5.4)<br />

P NL (t) =Re[P p exp(−iω p t)+P s exp(−iω s t)]. (8.5.5)<br />

The dependence of P p and P s on the pump and Stokes fields is found by substituting<br />

Eq. (8.5.4) in Eq. (8.5.1). The result is given by<br />

P j = 3ε [<br />

0<br />

4 χ(3) xxxx c 0 (E j · E j )E ∗ j + c 1 (E ∗ j · E j )E j<br />

+ c 2 (E ∗ m · E m )E j + c 3 (E m · E j )E ∗ m + c 4 (E ∗ m · E j )E m<br />

], (8.5.6)<br />

where j ≠ m and c 0 = 1 3 (1 − f R)+ 1 2 f b. The remaining coefficients are defin<strong>ed</strong> as<br />

c 1 = 2 3 (1 − f R)+ f a + 1 2 f b, c 2 = 2 3 (1 − f R)+ f a + 1 2 f b ˜h b (Ω), (8.5.7)<br />

c 3 = 2 3 (1 − f R)+ 1 2 f b + f a ˜h a (Ω), c 4 = 2 3 (1 − f R)+ 1 2 f b + 1 2 f b ˜h b (Ω), (8.5.8)<br />

with Ω = ω j − ω k . In arriving at Eq. (8.5.6), we made use of the relation ˜h a (0) =<br />

˜h b (0)=1.<br />

We can now introduce the Jones vectors |A p 〉 and |A s 〉 as in Section 7.6.1. To keep<br />

the following analysis relatively simple, we assume that both the pump and Stokes are<br />

in the form of CW or quasi-CW waves and neglect the dispersive effects. With this<br />

simplification, we obtain the following set of two coupl<strong>ed</strong> vector equations [189]:<br />

d|A p 〉<br />

dz<br />

d|A s 〉<br />

dz<br />

+ α p<br />

2 |A p〉 + i (<br />

2 ω pb l · σ|A p 〉 = iγ p c 1 〈A p |A p 〉 + c 0 |A ∗ p〉〈A ∗ p|<br />

)<br />

+ c 2 〈A s |A s 〉 + c 3 |A s 〉〈A s | + c 4 |A ∗ s 〉〈A ∗ s | |A p 〉, (8.5.9)<br />

+ α s<br />

2 |A s〉 + i (<br />

2 ω sb l · σ|A s 〉 = iγ s c 1 〈A s |A s 〉 + c 0 |A ∗ s 〉〈A ∗ s |<br />

)<br />

+ c 2 〈A p |A p 〉 + c 3 |A p 〉〈A p | + c 4 |A ∗ p〉〈A ∗ p| |A s 〉, (8.5.10)

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!