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Nonlinear Fiber Optics - 4 ed. Agrawal

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350 Chapter 9. Stimulat<strong>ed</strong> Brillouin Scattering<br />

4<br />

Stokes<br />

Normaliz<strong>ed</strong> Amplitude<br />

3<br />

2<br />

1<br />

Pump<br />

Acoustic<br />

0<br />

0 1 2 3 4 5 6 7 8 9 10<br />

Normaliz<strong>ed</strong> Time<br />

Figure 9.12: Temporal profiles associat<strong>ed</strong> with the pump, Stokes, and acoustic waves when the<br />

three form a Brillouin soliton for μ = 0.1 and b = 0.95.<br />

Figure 9.12 shows an example of the SBS-coupl<strong>ed</strong> solitons for μ = 0.1 and b =<br />

0.95. In this case, the Stokes wave travels backward in the form of a bright soliton at a<br />

velocity larger than v g by a factor of V . At the same time, the pump travels forward as<br />

a dark soliton. Another solution of Eqs. (9.4.13)–(9.4.15) shows that Stokes can also<br />

form a dark soliton, while the pump propagates as a bright soliton [96]. Such solitons<br />

exist even in the absence of GVD (β 2 = 0) and XPM (γ = 0) because they rely on the<br />

presence of a solitary acoustic wave. They are referr<strong>ed</strong> to as the Brillouin solitons and<br />

constitute an example of the so-call<strong>ed</strong> dissipative solitons because they can exist in<br />

spite of losses. Such solitons have been observ<strong>ed</strong> in a Brillouin-fiber ring laser [95].<br />

9.4.3 SBS-Induc<strong>ed</strong> Index Changes<br />

When the pump and Stokes pulses differ in their carrier frequencies by the Brillouin<br />

shift exactly (Ω = Ω B ), the Stokes falls on the Brillouin-gain peak and experiences<br />

the most gain. However, if Ω = ω p − ω s differs from Ω B by even a few MHz, the<br />

gain is r<strong>ed</strong>uc<strong>ed</strong> but, at the same time, the refractive index changes by a small amount<br />

because of the SBS-induc<strong>ed</strong> amplification. This can be seen from Eqs. (9.4.5)–(9.4.7)<br />

as follows. If we use the steady-state solution of Eq. (9.4.7) in Eq. (9.4.6), the Stokes<br />

wave satisfies<br />

− ∂A s<br />

∂z + 1 ∂A s<br />

v g ∂t<br />

+ α 2 A s = iγ(|A s | 2 +2|A p | 2 κ 1 κ 2 /A eff<br />

)A s +<br />

Γ B /2 + i(Ω − Ω B ) |A p| 2 A s , (9.4.20)<br />

where the last term represents the contribution of SBS. This term is complex for Ω ≠<br />

Ω B , and the imaginary part results from the SBS-induc<strong>ed</strong> index change by an amount

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