Abrir - Universidad Técnica de Ambato

DATOS:
N = 248
Nivel de Confianza = 95%
Valor de z = 1.96
E = 5% => 0.05
Ơ = p.q = (0.5*0.5) => 0.25
p = 50% => 0.5
q (1-p) = 0.5
Aplicando la fórmula, tenemos:
n= N*Ơ²*Z²
(N-1)*E²+Ơ²*Z²
n= 248x0.25²x1.96²
(248-1)0.05²+0.25²x1.96²
n= 248 (0.2401)
(247)0.0025+0.2401
n= 59.5448
0.6175+0.2401
n= 59.5448
n= 69.43
0.8576
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