CUAD. CONTROL I.pdf - Profe Saul

2 + B = 1B = 1 - 2B = -1−1L f ( s )−1L f ( s )2 −12 1= + = −S + 1 S + 2 S + 1 S + 2=−12 − 1L −S + 11LS + 2Comparamos en la tabla−1L f ( s )=−12 − 1L −S + 11LS + 2f ( t)= 2e− t− e−2tPolos múltiples−1L f ( s )2S + 2S− 2==2SAS+B+C2( S −1) S ( S −1)=[ ( S −1)] + B[ S −1]2S ( S −1)A S+ CS2=AS2− AS + BS − B + CS2S( S + 1)2S=2( A + C) + S( B − A)2S ( S + 1)− BA + C = 1B – A = 2-B = -2B = 2B – A = 22 – A = 2-A = 2 – 2A = 0A + C = 1C = 1−1L f ( s )0 2= +2S S+1( S −1)−1L f ( s )=−10 −12 −11 −11 −1L + L + L = 2 L + L2S S2( S −1) S ( S −1)1Tabla35