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chapter 3 rigid pavement - DOT On-Line Publications - Department ...

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SAMPLE DESIGN CALCULATIONS: The design of compression seals is a<br />

simple procedure. The following examples show how a design<br />

process could be used.<br />

EXAMPLE A:<br />

A State wants to use preformed compression seals on all new PCC<br />

<strong>pavement</strong> projects. Their standard design calls for a 60-foot<br />

joint spacing on a granular base. The expected temperature range<br />

is from 14'F to 90'F.<br />

Step 1 - Determine the anticipated joint movement.<br />

AL = CL (aAT + E:)<br />

= ( 0.8 )( 60 * 12 )[ ( 5.5*10* ) ( 76 ) + ( l.O*lO* ) ]<br />

= 576 ( 4.18*10d + l.O*lO‘* )<br />

= 0.3 inch<br />

Step 2 - Select width of uncompressed seal.<br />

(This particular sealant manufacturer recommends an<br />

operating range of 55 percent to 20 percent)<br />

W 2AL + (C, - C,)<br />

2 0.3 + ( 0.55 - 0.20 )<br />

1: 0.3 + 0.35<br />

2 0.86 inch<br />

use W = 1 inch<br />

Step 3 - Select width of sawcut.<br />

rusta11 PC = c* + .<br />

temr;, - *ln tem<br />

Maximum temp - Min temp 1;1<br />

Sc=(l -Pc)*W<br />

Case 1: Installation temperature = 80'F<br />

* (Cma - Glh)<br />

PC = 0.2 + [ ( 66 i 76 ) * ( 0.55 - 0.2 ) ]<br />

- 0.2 + ( 0.87 ) * ( 0.35 )<br />

- 0.50<br />

SC =(l- 0.5 ) * 1<br />

= 0.5 inch<br />

Case 2: Installation temperature = 40'F<br />

PC = 0.2 + [ ( 26 + 76 ) * ( 0.55 - 0.2 ) J<br />

= 0.2 + ( 0.34 ) * ( 0.35 )<br />

= 0.32<br />

SC =(l- 0.32 ) * 1<br />

= 0.68 inch<br />

33.7

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