chapter 3 rigid pavement - DOT On-Line Publications - Department ...
chapter 3 rigid pavement - DOT On-Line Publications - Department ...
chapter 3 rigid pavement - DOT On-Line Publications - Department ...
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SAMPLE DESIGN CALCULATIONS: The design of compression seals is a<br />
simple procedure. The following examples show how a design<br />
process could be used.<br />
EXAMPLE A:<br />
A State wants to use preformed compression seals on all new PCC<br />
<strong>pavement</strong> projects. Their standard design calls for a 60-foot<br />
joint spacing on a granular base. The expected temperature range<br />
is from 14'F to 90'F.<br />
Step 1 - Determine the anticipated joint movement.<br />
AL = CL (aAT + E:)<br />
= ( 0.8 )( 60 * 12 )[ ( 5.5*10* ) ( 76 ) + ( l.O*lO* ) ]<br />
= 576 ( 4.18*10d + l.O*lO‘* )<br />
= 0.3 inch<br />
Step 2 - Select width of uncompressed seal.<br />
(This particular sealant manufacturer recommends an<br />
operating range of 55 percent to 20 percent)<br />
W 2AL + (C, - C,)<br />
2 0.3 + ( 0.55 - 0.20 )<br />
1: 0.3 + 0.35<br />
2 0.86 inch<br />
use W = 1 inch<br />
Step 3 - Select width of sawcut.<br />
rusta11 PC = c* + .<br />
temr;, - *ln tem<br />
Maximum temp - Min temp 1;1<br />
Sc=(l -Pc)*W<br />
Case 1: Installation temperature = 80'F<br />
* (Cma - Glh)<br />
PC = 0.2 + [ ( 66 i 76 ) * ( 0.55 - 0.2 ) ]<br />
- 0.2 + ( 0.87 ) * ( 0.35 )<br />
- 0.50<br />
SC =(l- 0.5 ) * 1<br />
= 0.5 inch<br />
Case 2: Installation temperature = 40'F<br />
PC = 0.2 + [ ( 26 + 76 ) * ( 0.55 - 0.2 ) J<br />
= 0.2 + ( 0.34 ) * ( 0.35 )<br />
= 0.32<br />
SC =(l- 0.32 ) * 1<br />
= 0.68 inch<br />
33.7