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Principles of Fluorescence Spectroscopy

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PRINCIPLES OF FLUORESCENCE SPECTROSCOPY 211<br />

and is called the orientation polarizability. If the solvent has<br />

no permanent dipole moment, ε n 2 and ∆f - 0. Table 6.1<br />

lists representative values <strong>of</strong> ε, n and ∆f. From the magnitudes<br />

<strong>of</strong> ∆f one may judge that spectral shifts ∆ν will be<br />

considerably larger in water than in hexane.<br />

The interactions <strong>of</strong> a fluorophore with solvent can be<br />

described in terms <strong>of</strong> its ground- (µ G ) and excited-state (µ E )<br />

dipole moments, and the reactive fields around these<br />

dipoles. These fields may be divided into those due to electronic<br />

motions (R el G and R el E) and those due to solvent<br />

reorientation (R or G and R or E). Assuming equilibrium around<br />

the dipole moments <strong>of</strong> the ground and excited states, these<br />

reactive fields are<br />

RG el 2 µ G<br />

a3 f(n) REel 2µ E<br />

a<br />

R G or 2µ G<br />

3 f(n)<br />

a3 ∆f REel 2µ E<br />

∆f 3 a<br />

(6.8)<br />

Consider Figure 6.7, which describes these fields during the<br />

processes <strong>of</strong> excitation and emission. For light absorption<br />

the energies <strong>of</strong> the ground (E G ) and nonequilibrium excited<br />

(E E ) states are<br />

Figure 6.7. Effects <strong>of</strong> the electronic and orientation reaction fields on<br />

the energy <strong>of</strong> a dipole in a dielectric medium, µ E > µ G . The smaller circles<br />

represent the solvent molecules and their dipole moments.<br />

Energy E (absorption) E E V µ ER G or µ ER E el<br />

Energy G (absorption) E G V µ GR G or µ GR G el<br />

(6.9)<br />

(6.10)<br />

where E V represents the energy levels <strong>of</strong> the fluorophore in<br />

the vapor state, unperturbed by solvent. The absorption<br />

transition energy is decreased by the electronic reaction<br />

field induced by the excited state dipole. This occurs<br />

because the electrons in the solvent can follow the rapid<br />

change in electron distribution within the fluorophore. In<br />

contrast, the orientation <strong>of</strong> the solvent molecules does not<br />

change during the absorption <strong>of</strong> light. Therefore, the effect<br />

<strong>of</strong> the orientation polarizability, given by µ G R or G and µ E R or G,<br />

contains only the ground-state orientational reaction field.<br />

This separation <strong>of</strong> effects is due to the Franck-Condon principle.<br />

Recalling that energy is related to the wavelength by<br />

ν = ∆E/hc, subtraction <strong>of</strong> eq. 6.10 from 6.9 yields the energy<br />

<strong>of</strong> absorption:<br />

hcν A hc (ν A) V (µ E µ G)(R G or)<br />

µ ER E el µ GR G el<br />

(6.11)<br />

where hc(ν A ) V is the energy difference in a vapor where solvent<br />

effects are not present. By a similar consideration one<br />

can obtain the energy <strong>of</strong> the two electronic levels for emission.<br />

These are<br />

Energy E (emission) E E V µ ER E or µ ER E el<br />

Energy G (emission) E G V µ GR E or µ GR G el<br />

(6.12)<br />

(6.13)<br />

To derive these expressions we assumed that the solvent<br />

relaxed quickly in comparison to the lifetime <strong>of</strong> the excited<br />

state, so that the initial orientation field (R or G) changed to<br />

R or E prior to emission. The electronic field changed during<br />

emission, but the orientation field remained unchanged. The<br />

energy <strong>of</strong> the emission is given by<br />

hcν F hc(ν F) V (µ E µ G)R E or µ ER E el µ GR G el<br />

(6.14)<br />

In the absence <strong>of</strong> environmental effects one may expect ν A<br />

– ν F to be a constant for complex molecules that undergo<br />

vibrational relaxation. Hence, subtracting eq. 6.14 from<br />

6.11 yields

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