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Principles of Fluorescence Spectroscopy

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910 ANSWERS TO PROBLEMS<br />

dx rA A ( r0 dPA (13.52)<br />

Hence the maximum and minimum values <strong>of</strong> κ 2 are<br />

0.19 and 2.62 (eqs. 13.18 and 13.19). According to<br />

eqs. 13.23 and 13.24, the D–A distance can range<br />

from 0.81R 0 to 1.26R 0 , or from 20.3 to 31.5 Å.<br />

A13.9. If f A = 1.0 then the transfer efficiency is given by eq.<br />

13.13:<br />

(13.53)<br />

and the D–A distance is thus equal to R 0 . If f A = 0.5 the<br />

transfer efficiency is given by eq. 13.17:<br />

E 1 <br />

) 1/2<br />

0.71<br />

E 1 0.5<br />

0.5<br />

1.0<br />

0.5 1.0(0.5)<br />

1.0(0.5)<br />

1.0<br />

(13.54)<br />

If f A = 0.5 then the transfer efficiency for the actual<br />

D–A pair is 100%, and thus the D–A distance is less<br />

than 0.5R 0. The presence <strong>of</strong> acceptor underlabeling<br />

results in a higher intensity for the presumed D–A pair<br />

and an overestimation <strong>of</strong> the true D–A distance.<br />

A13.10. Equation 13.25 can be easily derived by writing<br />

expression for the acceptor intensity. In the absence<br />

(F A) and presence <strong>of</strong> donor (F AD) the intensities are<br />

given by<br />

F A(λ em<br />

A ) ε A(λ ex<br />

D )C A(λ em<br />

A )<br />

F AD(λ em<br />

A ) ε A(λ ex<br />

D ) Eε D(λ ex<br />

D )C A(λ em<br />

A )<br />

(13.55)<br />

(13.56)<br />

where excitation is at λ D , intensities are measured at<br />

λ A, and E is the transfer efficiency. C A(λ A em) is a constant<br />

relating the intensity at λ A to the acceptor concentration.<br />

Dividing 13.55 by 13.56, followed by<br />

rearrangement, yields eq. 13.25.<br />

If the extent <strong>of</strong> donor labeling is less than 1.0, then<br />

the acceptor intensities are given by<br />

F A(λ em<br />

A ) ε A(λ ex<br />

D )C A(λ em<br />

A )<br />

(13.57)<br />

F A(λ em<br />

A ) ε A(λ ex<br />

D ) f D E ε D(λ ex<br />

D )C A(λ em<br />

A )<br />

(13.58)<br />

where f D is the fractional labeling with the donor.<br />

These expressions can be understood by recognizing<br />

that the directly excited acceptor intensity is independent<br />

<strong>of</strong> f D , but the acceptor intensity due to energy<br />

transfer depends on f D . Rearrangement <strong>of</strong> eqs. 13.57<br />

and 13.58 yields 13.25.<br />

A13.11. Let C A (λ A ) and C D (λ A ) be the constants relating the<br />

intensities at λ A to the acceptor and donor concentrations,<br />

respectively, when both are excited at λ D . Since<br />

the donor is assumed to emit at λ A , eqs. 13.55 and<br />

13.56 become<br />

F A(λ A) ε A(λ D)C A(λ A)<br />

F AD(λ A) ε A(λ D) E ε D(λ D)C A(λ A)<br />

ε D(λ D)C DA(λ A)<br />

(13.59)<br />

(13.60)<br />

In eq. 13.58 we considered the contribution <strong>of</strong> the<br />

donor in the D–A pair to the intensity at λ A . In general<br />

C DA (λ A ) will be smaller than C D (λ A ) due to FRET<br />

quenching <strong>of</strong> the donor. However, C D (λ A ) can be<br />

measured with the donor-alone sample. C DA (λ A ) can<br />

be estimated using the shape <strong>of</strong> the donor emission to<br />

estimate the donor contribution at λ A in the doubly<br />

labeled sample. Eqs. 13.59 and 13.60 can be<br />

rearranged to<br />

FAD(λA) FD(λD) 1 E εD(λD) εA(λD) εD(λD)CDA(λA) εA(λD)CA(λA) (13.61)<br />

The transfer efficiency as seen from the acceptor<br />

emission is given by eq. 13.25, which assumes that the<br />

donor does not emit at the acceptor wavelength.<br />

Hence the acceptor emission increases the apparent<br />

efficiency to<br />

E app E C DA(λ A)<br />

C A(λ A)<br />

(13.62)<br />

and would thus be larger than the actual efficiency. If<br />

the donor does not contribute at λ A, then C DA(λ A) = 0

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