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Principles of Fluorescence Spectroscopy

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912 ANSWERS TO PROBLEMS<br />

B. A covalently linked acceptor is somewhat equivalent<br />

to one acceptor per sphere <strong>of</strong> 30 Å, or 8.84<br />

x 10 18 acceptors/cm 3 . This is equivalent to an<br />

acceptor concentration <strong>of</strong> 15 mM. Covalent<br />

attachment <strong>of</strong> an acceptor results in a high effective<br />

acceptor concentration.<br />

CHAPTER 15<br />

A.15.1. Using the data provided in Figure 15.28 one can calculate<br />

the following values:<br />

Mole% Rh-PE Rh-PE/Å 2 Rh-PE/R 0 2 F DA /F D<br />

0.0 0.0 0.0 1.0<br />

0.2 2.8 x 10 -5 0.071 0.62<br />

0.4 5.7 x 10 -5 0.143 0.40<br />

0.8 11.4 x 10 -5 0.286 0.21<br />

1.2 17.1 x 10 -5 0.429 0.15<br />

The distance <strong>of</strong> closest approach can be estimated by<br />

plotting the last two columns <strong>of</strong> this table on the simulations<br />

shown in Figure 15.17. The observed energy<br />

transfer quenching is greater than predicted for no<br />

excluded area, r C = 0, or much less than R 0. This suggests<br />

that the donors and acceptors are fully accessible<br />

and probably clustered in the PE vesicles. The R 0<br />

value was not reported in [64].<br />

A15.2. The decay times can be used with eq. 15.20 to obtain<br />

the transfer rate k T = 1.81 x 10 3 s –1 . Dividing by the<br />

EB concentration (2.77 µM) yields k T b = 6.5 x 10 8<br />

M –1 s –1 .<br />

Using eq. 15.25 and the values <strong>of</strong> R 0 and r C , the<br />

maximum bimolecular rate constant is 1.1 x 10 6 M –1<br />

s –1 . The measured values could be larger than the theoretical<br />

values for two reasons. The positively charged<br />

donors may localize around the negatively charged<br />

DNA. This results in a larger apparent concentration<br />

<strong>of</strong> EB. Given the small value <strong>of</strong> r C we cannot exclude<br />

the possibility <strong>of</strong> an exchange contribution to k T b.<br />

A15.3. To a first approximation the donor intensity is about<br />

50% quenched when C/C 0 = 0.5. This value <strong>of</strong> C/C 0<br />

can be used to calculate the acceptor concentration in<br />

any desired units, as listed in Table 15.3.<br />

Acceptor concentrations near 2 mM are needed in<br />

homogeneous solution. This is generally not practical<br />

for proteins because the absorbance due the acceptor<br />

would not allow excitation <strong>of</strong> the protein. Also, such<br />

high concentrations <strong>of</strong> acceptors are likely to perturb<br />

the protein structure.<br />

Table 15.3. Approximate Concentrations for 50%<br />

Quenching in One, Two, and Three Dimensions<br />

Concentrations for<br />

Equation 50% energy transfer<br />

C 0 = (4/3πR 0 3) –1 9.55 x 10 17 acceptors/cm 3 = 1.59 mM<br />

C 0 = (πR 0 2) –1 6.4 x 10 11 acceptors/cm 2 = 4.5 x 10 –3 acceptors/lipid<br />

C 0 = (2R 0 ) –1 5 x 10 5 acceptors/cm = 1.7 x 10 –2 acceptors/base pair<br />

The situation is much better in proteins and nucleic<br />

acids. In this case the acceptors need only to be about<br />

one per 222 lipids or one per 59 base pairs. This favorable<br />

situation is the result <strong>of</strong> a locally high concentration<br />

<strong>of</strong> acceptors due to their localization in the lipid<br />

or nucleic acid. The bulk concentration <strong>of</strong> acceptors<br />

can be low and is determined by the bulk concentration<br />

<strong>of</strong> membrane or nucleic acid.<br />

A15.4. The simulations in Figure 15.31 determine the R0 value because the two-dimensional concentration <strong>of</strong><br />

acceptors is known from the area/lipid and the fractional<br />

acceptor concentrations. Any point on these<br />

curves can be used to calculate R0 . For an acceptor<br />

density <strong>of</strong> 0.05 and t = τD the value <strong>of</strong> IDA (t)/I 0<br />

D is<br />

about 0.003. The value <strong>of</strong> β can be found from eq.<br />

15.9, yielding β = 2.41. For A/PL = 0.05 the area per<br />

acceptor molecule is C0 = 1400 Å/acceptor. Using eq.<br />

15.10 and 15.11 yields R0 = 39.8 Å, which agrees with<br />

the value <strong>of</strong> 40 Å given in [50].<br />

CHAPTER 16<br />

A16.1. A. Without experimentation, it is not possible to<br />

predict how the fluorescence properties <strong>of</strong> the<br />

protein will vary when it is unfolded. In general,<br />

one can expect the extent <strong>of</strong> tyrosine fluorescence<br />

to increase when the protein is unfolded.<br />

This could be detected by excitation at 280 nm.<br />

The tyrosine emission would appear near 308<br />

nm. It is also probable that the fluorescent intensity<br />

or the emission maxima <strong>of</strong> the single-tryptophan<br />

residue would change as the protein is<br />

unfolded. Once the spectral characteristics <strong>of</strong> the<br />

native and unfolded states are determined, the<br />

data can be used to quantify the unfolding<br />

process. It is important to remember that<br />

anisotropy or lifetime measurements may not

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