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Principles of Fluorescence Spectroscopy

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PRINCIPLES OF FLUORESCENCE SPECTROSCOPY 895<br />

A1.8. Figure 1.40 shows that the donor intensity increases<br />

and the acceptor intensity decreases upon addition<br />

<strong>of</strong> cAMP and PKI. These spectral changes<br />

indicate a decrease in RET. The donor and acceptor<br />

must move further apart when the protein binds<br />

cAMP or PKI. According to publications 43 the C<br />

and R subunits remain associated in the presence <strong>of</strong><br />

cAMP, but change this relative conformation (Figure<br />

1.43). PKI was said to dissociate the subunit.<br />

Figure 1.43. Effect <strong>of</strong> cAMP and protein kinase inhibitor (PKI) on the<br />

structure and association <strong>of</strong> cAMP-dependent protein kinase. The<br />

holoenzyme consists <strong>of</strong> two catalytic and two regulatory subunits.<br />

CHAPTER 2<br />

A2.1. The true optical density is 10. Because <strong>of</strong> stray light<br />

the lowest percent transmission (%T) you can measure<br />

is 0.01%. The %T <strong>of</strong> the rhodamine solution is much<br />

less than 0.01%. In fact I/I 0 = 10 –10 and %T = 10 –8 %.<br />

Hence your instrument will report an optical density<br />

<strong>of</strong> 4.0. The calculated concentration <strong>of</strong> rhodamine B<br />

would be 4 x 10 –5 M, 2.5-fold less than the true concentration.<br />

A2.2. The concentrations <strong>of</strong> solutions are 10 –5 and 10 –7<br />

M, respectively. A 1% error in %T means the OD<br />

can be<br />

OD log I 0<br />

I<br />

(2.13)<br />

Hence the concentration can be from 0.97 x 10 –5 to<br />

1.03 x 10 –5 M.<br />

For the more dilute solution, the 1% error results<br />

in a large error in the concentration:<br />

I0 OD log<br />

I<br />

1<br />

log<br />

0.51<br />

1.00<br />

log<br />

1.00<br />

or log 1<br />

0.49<br />

or log 1.0<br />

0.98<br />

(2.14)<br />

CHAPTER 3<br />

The measured OD ranges from 0 to 0.009, so the calculated<br />

concentration ranges from 0 to 2.9 x 10 –7 M.<br />

This shows that it is difficult to determine the concentration<br />

from low optical densities. In contrast, it is<br />

easy to obtain emission spectra with optical densities<br />

near 0.003.<br />

A3.1. Binding <strong>of</strong> the protein to membranes or nucleic acids<br />

could be detected by several types <strong>of</strong> measurements.<br />

The most obvious experiment would be to look for<br />

changes in the intrinsic tryptophan fluorescence upon<br />

mixing with lipid bilayers or nucleic acids. In the case<br />

<strong>of</strong> membranes one might expect the tryptophan emission<br />

to shift to shorter wavelengths due to shielding <strong>of</strong><br />

the indole moiety from water. The blue shift <strong>of</strong> the<br />

emission is also likely to be accompanied by an<br />

increase in the tryptophan emission intensity. In the<br />

case <strong>of</strong> nucleic acids, tryptophan residues are typically<br />

quenched when bound to DNA, so that a decrease<br />

in the emission intensity is expected.<br />

Anisotropy measurements <strong>of</strong> the tryptophan<br />

emission could also be used to detect binding. In<br />

this case it is difficult to predict the direction <strong>of</strong> the<br />

changes. In general one expects binding to result in<br />

a longer correlation time and higher anisotropy (see<br />

eq. 1.10), and an increase <strong>of</strong> the tryptophan<br />

anisotropy is likely upon binding to proteins. However,<br />

the anisotropy increase may be smaller than<br />

expected if the tryptophan lifetime increases on<br />

binding to the membranes (eq. 1.10).<br />

In the case <strong>of</strong> protein binding to nucleic acids, it<br />

is difficult to predict the anisotropy change. The<br />

tryptophan residues would now be in two states,<br />

free (F) and bound (B), and the anisotropy given by<br />

r = r F f F + r B f B , (3.2)<br />

where f F and f B represent the fraction <strong>of</strong> the total fluorescence<br />

from the protein in each state. If the protein<br />

is completely quenched on binding to DNA, then the<br />

anisotropy will not change because f B = 0. If the protein<br />

is partially quenched the anisotropy will probably<br />

increase, but less than expected due to the small contribution<br />

<strong>of</strong> the DNA-bound protein by the total fluorescence.

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