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Untitled - Aerobib - Universidad Politécnica de Madrid

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96 CHAPTER 4. COMBUSTION WAVES<br />

Finally, at the Chapman-Jouguet point α H = α, that is<br />

( ∂s2<br />

= 0. (4.21)<br />

∂τ 2<br />

)H<br />

From these three inequalities it results that the entropy of the burnt gases is<br />

minimum at the Chapman-Jouguet point and increases from there on, both in strong<br />

and weak <strong>de</strong>tonation branches.<br />

Since at point J condition (4.21) is satisfied, the isentropic passing through this<br />

point is tangent to the Hugoniot curve. Therefore, at point J the following conditions<br />

are satisfied<br />

α S = α H = α = α min . (4.22)<br />

These values, when taken into Eqs. (4.15) and (4.16), give at point J<br />

a 2 = v 2 , (4.23)<br />

thus resulting the following important property: in a Chapman-Jouguet <strong>de</strong>tonation<br />

the velocity of the burnt gases with respect to the wave is sonic. This property is<br />

the one that best characterizes a Chapman-Jouguet <strong>de</strong>tonation. As will presently be<br />

seen, owing to this property, the <strong>de</strong>tonations physically observed are of this same type.<br />

Jouguet stated this property in 1905 [3].<br />

For the purpose of <strong>de</strong>termining the character of v 2 in strong and weak <strong>de</strong>tonations,<br />

it is necessary, as previously seen in Fig. 4.3, to compare α and α s . This<br />

means that it is necessary to <strong>de</strong>termine the relative position of the isentropic that passes<br />

through each point of H, with respect to the straight line that joins P to that point. For<br />

the <strong>de</strong>termination of this relative position it is not sufficient to know the entropy variation<br />

along H, but it is also necessary to know the entropy variation along another<br />

direction, for instance, that of the radius vector with its origin at point P . This can<br />

easily be attained by consi<strong>de</strong>ring the function<br />

F (p 1 , τ 1 ; p 2 , τ 2 ) ≡ h 2 − h 1 − 1 2 (τ 1 + τ 2 ) (p 2 − p 1 ) . (4.24)<br />

On the Hugoniot curve H the value of this function is zero, as results from (4.10).<br />

This curve divi<strong>de</strong>s the plane in two regions: the lower region, that contains point P ,<br />

representative of the initial state, and the upper region. F takes opposite signs in both<br />

regions. As can be easily be verified, in the lower region F < 0 and in the upper<br />

region F > 0. For this purpose, it is enough to study, for instance, the sign of F in P .<br />

In B we have (Fig. 4.2)<br />

F (p 1 , τ 1 ; p 1 , τ 2 ) = h 2 (p 1 , τ 2 ) − h 1 (p 1 , τ 1 ) = 0. (4.25)

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