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Untitled - Aerobib - Universidad Politécnica de Madrid

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294 CHAPTER 12. DIFFUSION FLAME<br />

In particular, if condition<br />

D 12 = D 23 = D (12.28)<br />

is satisfied, Y as well as its <strong>de</strong>rivatives are continuous even at the flame. Continuity<br />

Eq. (12.1) for the mixture and Eq. (12.3) for motion still hold unchanged.<br />

As for the energy equation we shall assume that the specific heats at constant<br />

pressure of the three species are constant and equal<br />

c p1 = c p2 = c p3 = c p . (12.29)<br />

In such case, one can immediately check that Eq. (12.7) reduces to the following<br />

which hold throughout space.<br />

ρc p¯v · ∇T − ∇ · (λ∇T ) = 0, (12.30)<br />

Let us assume, that besi<strong>de</strong>s condition (12.28) the following is satisfied<br />

λ<br />

ρDc p<br />

= 1, (12.31)<br />

in accordance with the result of the elementary Kinetic Theory of Gases. Then, comparison<br />

between (12.25) and (12.30) suggests the existence of solutions of the form<br />

T = aY + b, (12.32)<br />

where a and b are constant but can be different for the interior and exterior regions.<br />

These solutions are available for the study of diffusion flames if boundary conditions<br />

can be satisfy through them. In particular, since on the flame Y = 0, temperature T b<br />

of the flame will be constant for the cases where Eq. (12.32) is valid. The study of<br />

diffusion flames reduces, hence, to a computation of the values for ρ , T , ¯v and Y . For<br />

this purpose, system of Eqs. (12.1) and (12.3) is available which must be completed<br />

with the boundary conditions a<strong>de</strong>quate for each case. These refer in general to the<br />

conditions at the discharge sections of fuel and oxidizer and at great distance from the<br />

flame. Let us assume, for example, that in the fuel’s discharge section<br />

and in the oxidizer’s discharge section<br />

Y = Y 10 , T = T 0 , (12.33)<br />

Y = Y 30 , T = T 0 , (12.34)<br />

Then Eq. (12.32) holds and one obtains in the interior region,<br />

T = T b − (T b − T 0 ) Y<br />

Y 10<br />

= T b − (T b − T 0 ) Y 1<br />

Y 10<br />

, (12.35)

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