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Untitled - Aerobib - Universidad Politécnica de Madrid

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64 CHAPTER 3. GENERAL EQUATIONS<br />

3.3 Equations of motion<br />

The equations of motion are obtained by applying Newton’s Second Law of Mechanics,<br />

to the material element in Fig. 3.1.<br />

Let V be the volume of said element. Then ρV will be the mass and ρV ¯v the<br />

momentum, for which the time variation when following the element is<br />

D (ρV ¯v)<br />

Dt<br />

= ρV D¯v<br />

Dt , (3.12)<br />

since ρV does not vary. Therefore, the variation of momentum of the mass contained<br />

in the unit volume is ρ (D¯v/Dt). Such variation originates from:<br />

1) The surface forces acting upon the unit volume.<br />

2) The mass forces acting upon the unit volume.<br />

Let us calculate both, separately.<br />

Let ¯f be the force that acts upon the surface element dσ at a point of Σ, Fig. 3.1.<br />

It has been shown in chapter 1 that ¯f is <strong>de</strong>termined by the stress tensor τ e of components<br />

τ ij and that as a function of the tensor it can be expressed as follows<br />

¯f = ¯n · τ e dσ, (3.13)<br />

where ¯n is the outward normal to the surface element dσ at the point. As it can easily<br />

be proved, the resultant of all forces ¯f per unit volume is ∇ · τ e . 6<br />

Let ¯F be the field intensity of the mass forces, that is to say, the force per unit<br />

mass. The force per unit volume is, evi<strong>de</strong>ntly, ρ ¯F . 7<br />

Now, by expressing Newton’s Second Law of Mechanics, we obtain<br />

ρ D¯v<br />

Dt = ∇ · τ e + ρ ¯F . (3.14)<br />

This vectorial equation is equivalent to three scalar equations corresponding to<br />

the three components of the reference system. For example, in rectangular cartesian<br />

coordinates, the component of this equation parallel to the coordinate axis x i (i =<br />

1, 2, 3) is<br />

ρ ∂v i<br />

∂t + ρv ∂v i<br />

j = ∂τ ij<br />

+ ρF i , (3.15)<br />

∂x j ∂x j<br />

6 In fact, the resultant of the forces acting upon Σ is RR Σ ¯n · τ e dσ. Now, by applying Ostrogradsky’s<br />

theorem we obtain RR Σ ¯n · τe dσ = RRR V ∇ · τe dV. Therefore, the force per unit volume is ∇ · τe.<br />

7 If the force per unit mass <strong>de</strong>pends on the species and ¯F i is the intensity for species A i , ρ ¯F must be<br />

substituted by P ρ i ¯Fi = ρ P Y i ¯Fi .<br />

i<br />

i

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