21.11.2014 Views

Untitled - Aerobib - Universidad Politécnica de Madrid

Untitled - Aerobib - Universidad Politécnica de Madrid

Untitled - Aerobib - Universidad Politécnica de Madrid

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

10.2. TSIEN METHOD 251<br />

As aforesaid, Tsien assumes that the velocity distribution of the burnt gases<br />

between A and C is linear, that is, u (Fig. 10.6) is given by the expression<br />

u = u 1 + (u e − u 1 )<br />

(1 − y )<br />

, (10.3)<br />

y 1<br />

where u e is the velocity on the axis of the chamber.<br />

Furthermore, Tsien assumes that the ratio λ of the <strong>de</strong>nsity of the unburnt gases<br />

to that of the burnt gases at each point of the flame front is constant. 1 Then, it can be<br />

easily shown that the <strong>de</strong>nsity of the burnt gases is constant between A and C and equal<br />

to ρ 1 /λ<br />

In fact, in D we have<br />

ρ = ρ 1<br />

λ . (10.4)<br />

ρ ′ 1<br />

ρ ′ 2<br />

= λ. (10.5)<br />

But due to the fact that the expansions of both unburnt and burnt gases between<br />

pressure p ′ in D and p in C are isentropic, there result<br />

and<br />

ρ ′ 1<br />

ρ 1<br />

=<br />

( ) 1 p<br />

′<br />

γ<br />

p<br />

(10.6)<br />

The combination of (10.5), (10.6) and (10.7) leads to (10.4).<br />

ρ ′ ( ) 1<br />

2 p<br />

′<br />

ρ = γ . (10.7)<br />

p<br />

Since pressure and <strong>de</strong>nsity of the burnt gases are constant between A and C, the<br />

temperature T of the burnt gases must also be constant between A and C, and equal to<br />

T 2<br />

T = T 2 = λT 1 = T e , (10.8)<br />

where T e is the temperature at A.<br />

The Bernoulli equation, when applied to the unburnt gas between u 0 and u 1 ,<br />

gives<br />

1<br />

2 u2 0 + c p T 0 = 1 2 u2 1 + c p T 1 . (10.9)<br />

If T 1 is eliminated by combining this equation with the equation<br />

( ) 1<br />

ρ 1 T1 γ − 1<br />

=<br />

ρ 0 T 0<br />

(10.10)<br />

1 Relation (9.36) in the preceding chapter proves that this ratio actually varies with the flame front incline.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!