21.11.2014 Views

Untitled - Aerobib - Universidad Politécnica de Madrid

Untitled - Aerobib - Universidad Politécnica de Madrid

Untitled - Aerobib - Universidad Politécnica de Madrid

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

10.3. METHOD OF FABRI-SIESTRUNCK-FOURÉ 257<br />

Moreover, it is immediately obtained that<br />

λ ′ = n − U ′ 2<br />

1 − U ′ 2 , (10.28)<br />

from which results<br />

′′<br />

ρ 1 T n − U ′ 2<br />

=<br />

ρ<br />

′′<br />

T 1 1 − U ′ 2 . (10.29)<br />

Bernoulli’s equation when applied to E, gives<br />

U ′′ 2 +<br />

T ′′<br />

T s,1<br />

= n. (10.30)<br />

Likewise, Bernoulli’s equation when applied to C for the unburnt gases, gives<br />

U 2 + T 1<br />

T s,1<br />

= 1. (10.31)<br />

By combining (10.29), (10.30) and (10.31), the following is obtained for U ′′<br />

√<br />

U ′′ nU<br />

=<br />

2 − U ′2 (n − 1 + U 2 )<br />

1 − U ′ 2<br />

. (10.32)<br />

Substituting (10.29) and (10.32) into (10.26), and making use of relation<br />

ρ 1<br />

ρ 0<br />

=<br />

the following equation is finally obtained<br />

( 1 − U<br />

2<br />

1 − U 2 0<br />

) 1<br />

γ − 1 , (10.33)<br />

( ) 1<br />

U 1 − U<br />

2<br />

γ − 1 − 1 + ψ<br />

U 0 1 − U0<br />

2 ∫ ψ<br />

= √ U (n − U ′2 )<br />

√ n<br />

0<br />

(1 − U ′2 )<br />

(U 2 − U ′ 2 n − 1 + U 2 ) dψ′ .<br />

n<br />

(10.34)<br />

This expression is an integral equation which <strong>de</strong>termines ψ as a function of U. Once<br />

the solution is known, the value of ψ gives the burnt fraction as a function of the<br />

velocity U of the gases at the point where the streamline ψ crosses the flame front.<br />

The flame width η = y/h is given by the expression<br />

η = 1 − ρ 0U 0<br />

(1 − ψ). (10.35)<br />

ρ 1 U<br />

To <strong>de</strong>termine the shape of the flame front, the abscissa ξ = x/h corresponding to ψ<br />

must also be known. This abscissa is given by the following expression<br />

ξ =<br />

∫ ψ<br />

0<br />

ρ 0 U 0<br />

ρ 1 ψ ′ dψ′ , (10.36)

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!