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Untitled - Aerobib - Universidad Politécnica de Madrid

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∆G 0 j = ∑ i<br />

1.7. CASE OF A MIXTURE OF IDEAL GASES 25<br />

and<br />

(<br />

Hi − T Si<br />

0 )<br />

νij (1.108)<br />

is the increase in free energy due to reaction j at temperature T of the mixture and<br />

at standard pressure p 0 . Thus ∆G 0 j <strong>de</strong>pends only on T . Table 1.2 gives the values of<br />

for several species corresponding to their formation from the chemical elements<br />

∆G 0 j<br />

at the standard state. Therefore Eq. (1.106) can be written<br />

∏<br />

( ) νj<br />

X νij p0<br />

i = Kj 0 (T ) , (j = 1, 2, . . . , r), (1.109)<br />

p<br />

i<br />

where Kj 0 is called the equilibrium constant of reaction j <strong>de</strong>pending only on temperature<br />

T . The values of Kj 0 versus T are given in Fig. 1.6, for several typical reactions<br />

of interest in combustion problems.<br />

30<br />

25<br />

1<br />

2H2 +OH ↔ H2O<br />

20<br />

log 10<br />

(K p<br />

)<br />

15<br />

10<br />

5<br />

0<br />

CO<br />

H 2 + 1 2O2 ↔ H2O<br />

CO 2 +H 2 ↔ CO +H 2O<br />

+ 1 2O2 ↔ CO2<br />

1<br />

2N2 +H2O ↔ NO +H2O<br />

H 2O ↔ H 2 +O<br />

1<br />

2 N2 + 1 2O2 ↔ NO<br />

1<br />

2 H2 ↔ H<br />

−5<br />

1<br />

2 N2 ↔ N<br />

−10<br />

0 400 800 1200 1600 2000 2400 2800 3200 3600<br />

T(K)<br />

Figure 1.6: Equilibrium constant of reaction vs temperature, for several typical reactions of<br />

interest in combustion problems.<br />

The chemical equations (1.84) used for this calculation can be any ones within<br />

the following limitations: a) they must be linearly in<strong>de</strong>pen<strong>de</strong>nt; b) their number must<br />

be the maximum that can exist between species. This number can be <strong>de</strong>termined when<br />

the phase rule is applied. Be l ′ < l the number of components of the mixture, then<br />

the number of in<strong>de</strong>pen<strong>de</strong>nt reactions will be l − l ′ . In turn l ′ can be <strong>de</strong>termined as<br />

follows: let E j , (j = 1, 2, . . . , l), be the chemical elements forming the species and<br />

a ij be the number of atoms of element E j in species A i . The number of components

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