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Untitled - Aerobib - Universidad Politécnica de Madrid

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5.6. DEFLAGRATIONS 125<br />

8<br />

7<br />

v/v 1<br />

=T/T 1<br />

6<br />

5<br />

4<br />

3<br />

−∆ P/(1/2)ρ 1<br />

v 1<br />

2<br />

T 2<br />

/T 1<br />

=8<br />

ρ D c p<br />

/λ=1.5<br />

2<br />

1<br />

Y<br />

0<br />

0 0.2 0.4 0.6 0.8 1<br />

ε<br />

Figure 5.6: Typical values of T , v, Y and ∆p in a <strong>de</strong>flagration as a function of the fraction<br />

of burnt gases .<br />

In this system the reaction rate w is a known function of Y and T . The pressure<br />

p is constant in virtue of Eq. (5.31). One must look for a solution of this system, in<br />

the interval 0 ≤ ε ≤ 1, satisfying the following boundary conditions<br />

ε = 0 : Y = 0, T = T 0 , (5.51)<br />

ε = 1 : Y = 1, T = T f . (5.52)<br />

Since this is a system of two first or<strong>de</strong>r equations, the four conditions (5.51)<br />

and (5.52) cannot be satisfied unless parameters e and m take well <strong>de</strong>fined values.<br />

Parameter e is given by the expression: e = q − c p T f , which results from expressing<br />

the condition w = 0 for ε = 1, that is, at the end of the combustion. As for m it must<br />

taken well <strong>de</strong>fined value, so that the previous differential system to be compatible.<br />

This means that weak <strong>de</strong>flagrations can only propagate with a well <strong>de</strong>fined velocity<br />

which <strong>de</strong>pends on the state of the mixture, its reaction rate and its coefficients of thermal<br />

conductivity and diffusion. The problem of <strong>de</strong>termining the propagation velocity<br />

of the flame through a combustible mixture appears, thus, as an “eigenvalue” problem.<br />

The solution to this problems will be studied in the following chapter.<br />

The same conclusions are reached when taking into account the influence of all<br />

the terms in the differential equations of the combustion wave, instead of consi<strong>de</strong>ring<br />

a limiting solution as done herein.

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