21.11.2014 Views

Untitled - Aerobib - Universidad Politécnica de Madrid

Untitled - Aerobib - Universidad Politécnica de Madrid

Untitled - Aerobib - Universidad Politécnica de Madrid

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

6.13. OZONE DECOMPOSITION FLAME 169<br />

Be Λ ij the parameter chosen to express the rest of them as functions of it. Once<br />

its value is known, the value for velocity u 0 of the flame, by virtue of Eqs. (6.22) and<br />

(6.132), is<br />

√<br />

u 0 =<br />

M iλ f B j T δj−nj<br />

f<br />

ρ 2 0 c p<br />

Λ −1/2<br />

ij . (6.139)<br />

6.13 Ozone <strong>de</strong>composition flame<br />

The ozone <strong>de</strong>composition flame in a mixture of this gas with oxygen is the first example<br />

we have chosen among the few cases of flame propagation which have been<br />

calculated. Its first theoretical study was due to Lewis and von Elbe [8] who thus became<br />

the first to analyze flame propagation consi<strong>de</strong>ring, in addition to the effects of<br />

heat transfer, those of the diffusion of reactants and products, as well as the influence<br />

of the radicals (oxygen atoms) in the process. For this purpose they applied the law of<br />

chemical reaction which inclu<strong>de</strong>s the influence of temperature and the concentrations<br />

of the various species on the reaction rate. The three chemical species in the process<br />

are ozone, molecular oxygen and atomic oxygen. Lewis and von Elbe simplified the<br />

problem by adopting the following assumptions:<br />

1) The Lewis-Semenov number for the mixture O 2 - O 3 is equal to unity. This<br />

assumption enables the expression of the concentrations of ozone and molecular<br />

oxygen as functions of temperature.<br />

2) The chemical processes take place in accordance with the following kinetic<br />

scheme<br />

O 3 ⇆ O 2 + O, (6.140)<br />

O + O 3 → 2 O 2 . (6.141)<br />

The first of these two reaction equations expresses that the concentration of<br />

atoms of oxygen at each point of the flame is the one that would correspond<br />

to a mixture of O, O 2 and O 3 in chemical equilibrium at the temperature and<br />

composition of the point.<br />

Having stated the problem, and if, furthermore, we take into account that the<br />

molar fraction of atomic oxygen is much smaller than unity, its solution is straightforward.<br />

In fact, the first of the above assumptions allows the expression of the molar<br />

fractions of O 2 and O 3 as functions of temperature, as shown in §9 of this chapter,<br />

and equation (6.140) allows the same for the molar fraction of O.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!