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Physical Principles of Electron Microscopy: An Introduction to TEM ...

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96 Chapter 4<br />

�<br />

(a) elastic<br />

z<br />

x<br />

m<br />

m<br />

(b) inelastic<br />

Figure 4-3. Hyperbolic trajec<strong>to</strong>ry <strong>of</strong> an incident electron during (a) elastic scattering (the case<br />

<strong>of</strong> a large-angle collision is indicated by the dashed curve) and (b) inelastic scattering.<br />

pro<strong>to</strong>ns + neutrons in the nucleus), essentially the a<strong>to</strong>mic weight <strong>of</strong> the a<strong>to</strong>m.<br />

For a hydrogen a<strong>to</strong>m (A = 1), m/M � 1/1836 and Eq. (4.8) gives E/E0 <<br />

0.002, so for 180-degree scattering only 0.2% <strong>of</strong> the kinetic energy <strong>of</strong> the<br />

electron is transmitted <strong>to</strong> the nucleus. For other elements, and especially for<br />

smaller scattering angles, this percentage is even lower. Scattering in the<br />

electrostatic field <strong>of</strong> a nucleus is therefore termed elastic, implying that the<br />

scattered electron retains almost all <strong>of</strong> its kinetic energy.<br />

4.2 <strong>Electron</strong>-<strong>Electron</strong> Scattering<br />

If the incident electron passes very close <strong>to</strong> one <strong>of</strong> the a<strong>to</strong>mic electrons that<br />

surround the nucleus, both particles experience a repulsive force. If we<br />

ignore the presence <strong>of</strong> the nucleus and the other a<strong>to</strong>mic electrons, we have a<br />

two-body encounter (Fig. 4-3b) similar <strong>to</strong> the nuclear interaction depicted in<br />

Figs. 4-2 and 4-3a. Equations (4.1) <strong>to</strong> (4.6) should still apply, provided we<br />

replace the nuclear mass M by the mass m <strong>of</strong> an a<strong>to</strong>mic electron (identical <strong>to</strong><br />

the mass <strong>of</strong> the incident electron, as we are neglecting relativistic effects). In<br />

this<br />

case, Eq. (4.6) becomes:<br />

E/E0 = 1 + v1 2 /v0 2 � 2 (v1/v0) cos� (4.9)<br />

Because Eq. (4.9) no longer contains the fac<strong>to</strong>r (m/M), the energy loss E can<br />

be much larger than for an elastic collision, meaning that scattering from the<br />

electrons that surround an a<strong>to</strong>mic nucleus is inelastic. In the extreme case <strong>of</strong><br />

a head-on collision, v1 � 0 and E � E0 ; in other words, the incident electron<br />

loses all <strong>of</strong> its original kinetic energy. In practice, E is in the range 10 eV <strong>to</strong><br />

50 eV for the majority <strong>of</strong> inelastic collisions. A more correct treatment <strong>of</strong><br />

inelastic scattering is based on wave-mechanical theory and includes the<br />

collective<br />

response <strong>of</strong> all <strong>of</strong> the electrons contained within nearby a<strong>to</strong>ms.

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