27.06.2021 Views

F. K. Kong MA, MSc, PhD, CEng, FICE, FIStructE, R. H. Evans CBE, DSc, D ès Sc, DTech, PhD, CEng, FICE, FIMechE, FIStructE (auth.)-Reinforced and Prestressed Concrete-Springer US (1987)

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

200 Shear, hand and tarsian

where Vis the shear force acting on the beam section, d the effective depth

and b v the beam width. For a rectangular beam, b v is taken as the width b;

for a f1anged beam, it is taken as the web width b w . Section 6.4 will show

how design shear stresses are used in practice.

In the meantime, let us retum to Fig. 6.2-1(a) and study how the

rectangular beam fails eventually as the shear force V is increased. Many

tests [1, 2] have established that the failure mode is strongly dependent on

the shear-span/depth ratio avfd:

(a) avfd > 6: Beams with such a high avfd ratio usually fail in bending.

(b) 6> avfd > 2.5: Beams with avid lower than about 6 tend to fail in

shear. With reference to Fig. 6.2-1(a), as the force Vis increased,

the ftexural crack a-b nearest the support would propagate towards

the loading point, gradually becoming an inclined crack, which is

known as a f1exure-shear crack but which is of ten referred to simply

as a diagonal crack (Fig. 6.2-2: crack a-b-c). With further increase

in V, failure usually occurs in one of two modes. It the avf d ratio is

relatively high, the diagonal crack would rapidly spread to e, resulting

in collapse by splitting the beam into two pieces. This mode of failure

is of ten called diagonal-tension failure; for such a failure mode, the

ultimate load is sensibly the same as that at the formation of the

diagonal crack. It the avf d ratio is relatively low, the diagonal crack

tends to stop somewhere at j (Fig. 6.2-2); a number of random

cracks may develop in the concrete around the longitudinal tension

reinforcement. As Vis further increased, the diagonal crack widens

and propagates along the level of the tension reinforcement (Fig.

6.2-2: crack g-h). The increased shear force presses down the

longitudinal steel and causes the destruction of the bond between the

concrete and the steel, usually leading to the splitting of the concrete

along g-h. It the longitudinal reinforcement is not hooked at the

end, the destruction of bond and the concrete splitting will cause

immediate collapse. It hooks are provided, the beam behaves like a

two-hinge arch until the increasing force in the longitudinal reinforcement

destroys the concrete surrounding the hooks, whence

Fig. 6.2-2

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!