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F. K. Kong MA, MSc, PhD, CEng, FICE, FIStructE, R. H. Evans CBE, DSc, D ès Sc, DTech, PhD, CEng, FICE, FIMechE, FIStructE (auth.)-Reinforced and Prestressed Concrete-Springer US (1987)

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10 Limit state design concepts

for

x = 50 N/mm 2 , z = 50 S 45 = 1

for

x = 60 N/mm 2 z = 60 - 45 = 3

From Table 1.3-3,

' 5

area between z = 0 and z = 3 is 0.4987

area between z = 0 and z = 1 is 0.3413

Therefore

area between z = 1 and z = 3 is 0.4987 - 0.3413 = 0.1574

(b) We want the limits of z between which the area under the normal

probability curve is 0.999. Because of symmetry, the area between

z = 0 and z = z is half of 0.999, i.e. 0.4995. From Table 1.3-3,

z = 3.3. Therefore

x =.X± 3.3a = 45 N/mm 2 ± 3.3 x 5 N/mm2

= 28.5 N/mm 2 or 61.5 N/mm 2

Ans. (a) There is a probability of 15.74% that a random cube would

have a strength between 50 and 60 N/mm 2 •

(b) There is a 99.9% probability that the whole range of cube

strengths is from 28.5 to 61.5 N/mm 2 •

Level of significance and confidence level

If a set of values are normally distributed, then the probability of any single

value falling between the limits .X ± za is the area of the normal probability

curve (Fig. 1.3-3 and Table 1.3-3) between these limits. This

probability, expressed as a percentage, is called the confidence level, or

confidence coefficient. The limits (.X - za) and (.X + za) are called the

confidence limits and the interval (.X - za) to (.X + za) is called the

confidence interval. The probability of any single value falling outside the

limits .X ± za is given by the areas under the two tails of the normal

probability curve outside these limits; this probability, expressed as a

percentage, is called the level of significance.

Example 1.3-4

It is known that a set of test results (which are normally distributed) has a

mean strength of 82.4 N/mm 2 and a standard deviation of 4.2 N/mm 2 •

Determine:

(a) the 95% confidence limits;

(b) the strength limits at the 5% level of significance; and

(c) the strength below which 5% of the test results may be expected to

fall.

SOLUTION

(a) With reference to Fig. 1.3-3 and Table 1.3-3, we wish to determine

the limits of z such that the area below the normal curve between

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