F. K. Kong MA, MSc, PhD, CEng, FICE, FIStructE, R. H. Evans CBE, DSc, D ès Sc, DTech, PhD, CEng, FICE, FIMechE, FIStructE (auth.)-Reinforced and Prestressed Concrete-Springer US (1987)

428 Practical design and detailing
BS 8110 does not allow zld to be taken as more than 0.95 in any
case.)
From eqn (4.6-12),
M (24. 7) (10 6 ) 2
As = (0.87)/yz = (0.87) (460) (0.94) (154) = 426 mm /m
From Section 8.8,
Hence
minimum tension steel = 0.13% bh = 234 mm 2 /m
< 426 mm 2 /m
As = 426 mm 2 /m OK
From Table A2-2,
Midspan: fc::d 2 = 0.026 (as at supports)
Step 5 Shear (see Section 8. 7)
From Table 11.4-2,
Top: TlO at 150 (523 mm 2 /m)
Bottom: T10 at 150 (523 mm 2 /m)
V = 0.5F = (0.5) (71.3 from Step 2) = 35.7 kN/m
v (35.7) (10 3 ) 2
v = bvd = (1000) (154) = 0.23 N/mm
From Table 6.4-1,
< 0.8yfcu (= 5.1 N/mm 2 )
For Aslbvd = 523/(1000) (154) = 0.34%
Vc = 0.65 N/mm 2 > v
From Section 8.7,
Step 6 Deflection (see Section 8.8)
From Table 5.3-1,
basic span/ depth ratio = 26
Shear resistance OK
M (24. 7) (10 6 )
bd2 = (1000) (1542) = l.04
From Table 5.3-2,
Hence
modification factor = 1.38
allowable span/depth ratio = (26) (1.38) = 35.9