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F. K. Kong MA, MSc, PhD, CEng, FICE, FIStructE, R. H. Evans CBE, DSc, D ès Sc, DTech, PhD, CEng, FICE, FIMechE, FIStructE (auth.)-Reinforced and Prestressed Concrete-Springer US (1987)

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394 Prestressed concrete continuous beams

saved by trying concordant profiles; in this respect, Rule 4 is helpful.

Rule 5 will be found useful if the trial profile has to be modified while

maintaining its concordancy (see Example 10.3-1(b) ).

StepS

If the profile selected in Step 4 is such that the tendon is too near the

beam top or the beam soffit at a section, increased concrete cover may

be achieved by linear transformation-which renders the tendon nonconcordant

but which does not affect the position of the line of pressure.

Similarly, if the 'kink' or change of slope of the tendon is too sharp

over a support (consequence: too much loss of prestress due to friction),

this may be eased by linear transformation; for example, in Fig. 10.3-2,

the 'kink' over the interior support is less in the profile (b) than in the

profile (a).

Step6

Check stresses at transfer and calculate loss of prestress; revise design as

necessary.

Step7

Check ultimate flexural strength and ultimate shear resistance at critical

sections. See Sections 9.5 and 9.6.

StepS

Design end blocks if necessary [1, 2].

Example 10.5-1

A post-tensioned beam of uniform cross-section is continuous over three

equal spans of 10 m, and carries imposed loads of 100 kN acting

simultaneously at each of the third-span points. The allowable stresses in

service are /a max = 14 N I mm 2 , /amin = 0 and those at transfer are /amaxt =

16 N/mm 2 and /amint = -1 N/mm2• The prestress loss ratio (ratio of the

prestressing force in service to that at transfer) is a = 0.85. Design:

(a)

(b)

(c)

SOLUTION

the concrete section;

the prestressing force; and

the tendon profile.

Step I

The reader should verify that the imposed-load moments Mi and the

dead-load moments Md are as shown in Fig. 10.5-1.

By inspection, section B is critical. From eqn (10.4-9),

Z(min) = Mimax - Mimin = 0 - ( -266) = 19 .0 x 106 mm3

famax - famin 14 - 0

To obtain a reasonable depth of the permissible zone for the line of

pressure, choose a section with, say, the following properties:

Z 1 (bottom) = 22 x 10 6 mm3 Z2(top) = 23 x 10 6 mm3

area A = 160,000 mm 2

overall depth h = 770 mm

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