LECTURE PHYSICAL CHEMISTRY 3rd EDITION ROBERT G. MORTIMER

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The same approximation holds for a solid–vapor
transition. From Eqs. (5.3-8) and (5.3-12) we obtain the
derivative form of the Clausius–Clapeyron equation.
For a liquid–vapor transition
- For sublimation (a solid–vapor transition), ∆ vap H m is
replaced by ∆ sub H m , the molar enthalpy change of
sublimation.To obtain a representation of P as a
function of T , we need to integrate Eq. (5.3-13).We
multiply by dT and divide by P:
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