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Untitled - Kelly Walsh High School

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Gases 81<br />

Quick Tip<br />

Don’t Forget!<br />

moles of gas) constant, that is, no gas can get in or out; we can express the relationship<br />

between the other three by the combined gas equation:<br />

P 1 V 1<br />

T 1<br />

P 2 V 2<br />

T 2<br />

1 and 2 refer to the initial and final conditions of the gas, respectively.<br />

In any gas law calculation, you must express the temperature in Kelvin.<br />

For example, suppose you have a balloon occupying a volume of 10.0 L at an<br />

internal pressure of 1.50 atm at 20. o C. It is heated to 70. o C and the pressure is<br />

determined to be 2.00 atm. We can calculate the new volume using the combined<br />

gas law.<br />

We will be solving the combined gas equation for V 2, so we will take the combined<br />

gas law and rearrange for V 2:<br />

V 2 P 1 V 1 T 2<br />

T 1 P 2<br />

The temperatures must be expressed in Kelvin. 20.C 293 K (K C 273)<br />

and 70.C 343 K.<br />

Substituting in the values:<br />

V 2 <br />

(1.50 atm) (10.0 L) (343 K)<br />

(293 K) (2.00 atm)<br />

8.77986 8.78 L<br />

In the combined gas equation, we held just the amount constant. If, however,<br />

we hold two quantities constant and look at the relationship between the other<br />

two we can derive the other common gas laws shown below in Table 5-1.

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