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Untitled - Kelly Walsh High School

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Kinetics 199<br />

reaction is first order.” In some cases, the order comes indirectly from the problem,<br />

for example, “the rate law is Rate k[A] 2 , which means the reaction is<br />

second order.”<br />

In most problems, it will be to your advantage to find and label as many of the<br />

following terms as possible: [A] 0, [A] t, k, t, and t 1/2. You will not need all these<br />

terms for all problems. However, the ones you have, or do not have, often direct<br />

you towards the solution.<br />

Let’s apply the preceding two paragraphs to an example problem. The firstorder<br />

decomposition of gaseous dinitrogen pentoxide, N 2O 5, to nitrogen dioxide,<br />

NO 2, and oxygen, O 2, has a rate constant of 4.9 10 4 s 1 at a certain temperature.<br />

Calculate the half-life of this reaction.<br />

This is a first-order reaction. The following relationships apply to first-order<br />

reactions:<br />

Rate k[A] ln [A] 0<br />

kt t1/2 <br />

[A] t<br />

0.693<br />

k<br />

These are the only equations we have exclusive to first-order reactions. For this<br />

reason, one or more of these equations will be necessary to work the problem.<br />

(In this problem, A N 2O 5.)<br />

Using the list of terms ([A] 0, [A] t, k, t, and t1/2), and the given information, we<br />

find that k = 4.9 104 s1 and t1/2 ? (We are using a “?” to indicate the term<br />

we are seeking.) The only first-order relationship we have that relates k and t1/2 0.693<br />

is t1/2 k . This significantly limits our options to finishing the problem. To finish<br />

the problem, we need to enter k into the relationship:<br />

t1/2 0.693<br />

k <br />

0.693<br />

4.9 104 s1 1414.2857 1.4 103 s<br />

Let’s try another example. A substance undergoes a simple decomposition. The<br />

reaction is first order. In one experiment, at 25°C, the concentration of this substance<br />

decreased from 1.000 M to 0.355 M after 4.25 min. What was the rate constant<br />

for this reaction?<br />

In this case, as in the preceding example, we have a first-order reaction. This limits<br />

us to the same set of three relationships as in the earlier example. Using the list<br />

of terms ([A] 0, [A] t, k, t, and t1/2), and the given information, we find that k ?,<br />

[A] 0 1.000 M, [A] t 0.355 M, and t 4.25 min. (We also know T 25°C, but<br />

since T is not one of the five terms, this is irrelevant.). The only first-order<br />

[A]<br />

0<br />

relationship with these four terms is ln [A] kt. We can either enter the given values<br />

t<br />

into this equation, or we can rearrange the equation before entering the values.

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