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Untitled - Kelly Walsh High School

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Chemical Equilibria 211<br />

Careful!<br />

Don’t Forget!<br />

Even when the same reaction is involved, the K may be different. This is because<br />

the value of K changes with temperature. Always use the specified K even if it is<br />

different from a similar example.<br />

The first step in this, and most equilibria problems, should begin by writing the<br />

equilibrium constant expression. In this case, the expression is:<br />

[NH3 ]<br />

Kc <br />

2<br />

[N2 ][H2 ] 3<br />

The problem gives us: [N2] 2.00 M and [H2] 3.00 M. The next step is to<br />

enter the given values into the equilibrium constant expression and rearrange<br />

the expression to isolate the ammonia. Some people find it easier to reverse<br />

these steps.<br />

Kc 2.42 103 [NH3 ] 2<br />

[2.00] [3.00] 3<br />

[NH3 ] 2<br />

[N2 ][H2 ] 3<br />

[NH3] 2 2.42 103 [2.00] [3.00] 3 0.13068 (unrounded)<br />

[NH3] 20.13068 0.361497 0.361 M NH3 Determine the value of K p for the following equilibrium: C(s) CO 2(g) K<br />

2CO(g). At equilibrium, the carbon monoxide, CO, pressure is 1.22 atm and the<br />

carbon dioxide, CO 2, pressure is 0.780 atm.<br />

The first step in this, and most equilibria problems, should begin by writing the<br />

equilibrium constant expression. In this case, the expression is for a K p so pressures<br />

must be present. The expression is:<br />

K p P2 CO<br />

P CO2<br />

Never include a solid in an equilibrium expression.

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