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Untitled - Kelly Walsh High School

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298 CHEMISTRY FOR THE UTTERLY CONFUSED<br />

Substituting this rate constant into equation (1):<br />

ln (65/100) (1.21 10 4 y 1 ) t<br />

0.4308 (1.21 10 4 y 1 ) t<br />

t 3560.33 3.6 × 10 3 y<br />

20-4 Mass/Energy Conversions<br />

Don’t Forget!<br />

Whenever a nuclear decay or reaction takes place, it releases energy. This<br />

energy may be in the form of heat and light, gamma radiation, or kinetic energy<br />

of the expelled particle and recoil of the remaining particle. This energy results<br />

from the conversion of a very small amount of matter into energy.<br />

In a nuclear reaction, there is no conservation of matter as in ordinary chemical<br />

reactions.<br />

The amount of energy that is produced can be calculated by using Einstein’s<br />

relationship, E mc 2 , where E is the energy produced, m is the mass converted<br />

into energy (the mass defect) and c is the speed of light. The amount of matter<br />

converted into energy is normally very small, but when we multiply it by the<br />

speed of light (a very large number) squared, the amount of energy produced is<br />

very large.<br />

When 1 mol of U-238 decays to Th-234, 5 10 6 kg of matter is converted to<br />

energy (the mass defect). Calculate the amount of energy released.<br />

Solution:<br />

E mc 2<br />

E (5 10 6 kg) (3.00 10 8 m/s) 2<br />

E 4.5 10 11 kgm 2 /s 2 5 10 11 kgm 2 /s 2 5 10 11 J

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