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Untitled - Kelly Walsh High School

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100 CHEMISTRY FOR THE UTTERLY CONFUSED<br />

The coffee-cup calorimeter can be used to measure the heat changes in reactions<br />

that are open to the atmosphere, q p, constant pressure reactions. We use<br />

this type of calorimeter to measure the specific heats of solids. We heat a known<br />

mass of a substance to a certain temperature and then add it to the calorimeter<br />

containing a known mass of water at a known temperature. The final temperature<br />

is then measured. We know that the heat lost by the added substance (the<br />

system) is equal to the heat gained by the surroundings (the water and<br />

calorimeter, although for simple coffee-cup calorimetry the heat gained by the<br />

calorimeter is small and often ignored):<br />

q solid q water<br />

Substituting the relationships for q gives:<br />

(c solid mass solid T solid) (c water mass water T water)<br />

We can then solve this equation for the specific heat capacity of the solid.<br />

We use the constant-volume bomb calorimeter to measure the energy changes<br />

that occur during combustion reactions. We add a weighed sample of the substance<br />

under investigation to the calorimeter and then add excess compressed<br />

oxygen gas. We ignite the sample electrically and measure the temperature<br />

change of the calorimeter and the known mass of water. Generally, we know the<br />

heat capacity of the calorimeter and can determine heat absorbed by the water.<br />

Suppose we have a problem such as the one below:<br />

We ignited a 1.5886 g sample of glucose (C 6H 12O 6) in a bomb calorimeter. The<br />

temperature increased by 3.682C. The heat capacity of the calorimeter was<br />

3.562 kJ/C, and the calorimeter contained 1.000 kg of water. Find the molar heat<br />

of reaction (J/mol of glucose) for the reaction:<br />

C 6H 12O 6(s) 6 O 2(g) l 6 CO 2(g) 6 H 2O(l)<br />

In solving problems of this type, you must realize that the oxidation of the glucose<br />

released energy in the form of heat and that some of the heat was absorbed<br />

by the water and the remainder by the calorimeter. You can use both the heat<br />

capacity of the calorimeter and the mass and specific heat of the water with the<br />

temperature change to calculate the heat absorbed by the calorimeter and<br />

water:<br />

(Heat capacity of the calorimeter) (change in temperature)<br />

Heat absorbed by the calorimeter<br />

(Grams of water) (specific heat of water) (temperature change)<br />

Heat absorbed by the water

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