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Untitled - Kelly Walsh High School

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Kinetics 193<br />

Don’t Forget!<br />

the concentration of HI to drop from 0.200 M to 0.190 M at 25°C? Answer:<br />

1.10 10 20 s<br />

This is a simple plug-in problem, with k 2.40 10 21 /M s, [A] 0 0.200 M, and<br />

[A] t 0.190 M. You may simply plug in the values and then solve for t, or you first<br />

rearrange the equation to give t (1/[A] t 1/[A] 0)/k. You will get the same<br />

answer in either case. If you get a negative answer, you interchanged [A] t and [A] 0.<br />

The order of reaction can be determined graphically by using the integrated<br />

rate law. If a plot of the ln[A] versus time yields a straight line, then the reaction<br />

is first order with respect to reactant A. If a plot of 1/[A] versus time yields<br />

a straight line, then the reaction is second order with respect to reactant A.<br />

The reaction half-life, t 1/2, is the amount of time that it takes for a reactant concentration<br />

to decrease to one-half its initial concentration. For a first-order<br />

reaction, the half-life is a constant, independent of reactant concentration and<br />

has the following relationship:<br />

t 1/2 <br />

For second-order reactions, the half-life does depend on the reactant concentration.<br />

We calculate it using the following formula:<br />

t 1/2 <br />

0.693<br />

k<br />

Radioactive decay is a first-order process. See Chapter 20 for a discussion of<br />

half-lives related to nuclear reactions and other information on radioactivity.<br />

The rate constant for the radioactive decay of thorium-232 is 5.0 10 11 /year.<br />

Determine the half-life of thorium-232.<br />

This radioactive decay process follows first-order kinetics. Substitute the value<br />

of k into the appropriate equation:<br />

t 1/2 0.693/k 0.693/5.0 10 11 year 1 1.4 10 10 year<br />

1<br />

k[A] 0<br />

The half-life must have units of time never time 1 .

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