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Untitled - Kelly Walsh High School

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74 CHEMISTRY FOR THE UTTERLY CONFUSED<br />

Quick Tip<br />

The calculation will begin as in the first example in this section:<br />

(0.200 mol HC2H3O2 ) a 1 mol Ca(OH) 2<br />

b<br />

2 mol HC2H3O2 This will give us the moles of calcium hydroxide instead of the grams, thus we<br />

need to add another step. We have moles and we need grams, the molar mass<br />

relates these two quantities. We determine the molar mass by using the formula<br />

and the atomic weights found in a table such as the periodic table.<br />

Anytime the problem deals with the moles and the mass of a substance, you will<br />

very, very likely need to know the molar mass (molecular weight) of the substance<br />

to complete the problem.<br />

The molar mass of calcium hydroxide is 74.10 g/mol. We can add the molar mass<br />

to our calculation to convert our moles to grams:<br />

(0.200 mol HC2H3O2 ) a 1 mol Ca(OH) 2<br />

ba<br />

2 mol HC2H3O2 74.10 g Ca(OH) 2<br />

b<br />

1 mol Ca(OH) 2<br />

7.41 g Ca(OH) 2<br />

This calculation leaves us with the appropriate number of significant figures and<br />

the correct units.<br />

Now let’s work one of the more typical titration problems. What is the concentration<br />

of a calcium hydroxide solution if 0.0250 L of a calcium hydroxide solution<br />

were necessary to titrate 0.0400 L of a 0.100 M acetic acid solution? We have<br />

more information, but this does not change our first step of transferring this<br />

information to the balanced chemical equation. You should recognize that by<br />

“concentration,” the problem means molarity.<br />

2 HC 2H 3O 2(aq) Ca(OH) 2(aq) l Ca(C 2H 3O 2) 2(aq) 2 H 2O(l)<br />

0.0400 L ? M<br />

0.100 M 0.0250 L

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