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Untitled - Kelly Walsh High School

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84 CHEMISTRY FOR THE UTTERLY CONFUSED<br />

Don’t Forget!<br />

Quick Tip<br />

The oxygen gas that forms occupies a volume of 550. mL at 27C. The atmospheric<br />

pressure is 731.3 torr.<br />

In using any of the gas laws, be sure to express the temperature in Kelvin.<br />

At this point, you now have 550. mL of oxygen gas at 731.3 torr and 300. K<br />

(27 o C 273). From this data, you can use the ideal gas equation to calculate the<br />

number of moles of oxygen gas produced:<br />

PV nRT<br />

n PV/RT<br />

You will need to convert the pressure from torr to atm:<br />

(731.3 torr) (1 atm/760.0 torr) 0.9622 atm<br />

and express the volume in liters: 550. mL (1 L/1000 mL) 0.550 L<br />

Now you can substitute these quantities into the ideal gas equation:<br />

n (0.9622 atm) (0.550 L)/(0.0821 Latm/Kmol) (300. K)<br />

n 0.021486 mol O 2 (unrounded)<br />

Be sure, especially in stoichiometry problems involving gases, that you are calculating<br />

the values such as volume and pressure of the correct gas. You can<br />

avoid this mistake by clearly labeling your quantities that means, mol of O 2<br />

instead of just mol.

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