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Medium Voltage Application Guide

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13721.A<br />

Percentage DC component<br />

SWITCHGEAR<br />

Exercise<br />

What is the required short circuit breaking capacity of a circuit breaker, with a pole opening time of 45 ms and an<br />

expected symmetrical short circuit fault level of 21 kA at the point of installation?<br />

Total opening time of the circuit breaker: t = 10 + 45 = 55 ms<br />

The percentage DC component at a total opening time of 55 ms is 30%:<br />

100<br />

90<br />

80<br />

70<br />

60<br />

50<br />

40<br />

1 = 45 ms<br />

30<br />

20<br />

10<br />

0<br />

0 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90<br />

Time interval from initiation of short circuit current (ms)<br />

The asymmetrical fault current level is 23 kA. A circuit breaker with a rated short circuit breaking capacity (I sc ) of<br />

25 kA can be used.<br />

710-12280-00A <strong>Medium</strong> <strong>Voltage</strong> <strong>Application</strong> <strong>Guide</strong> Page 93

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