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Preparatory Notes for ASNT NDT Level III Examination - Ultrasonic Testing, UT

Preparatory Notes for ASNT NDT Level III Examination - Ultrasonic Testing

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Q: Calculate the maximum shear wave angle and the range <strong>for</strong> 360°<br />

revolution scanning when the shear wave angle is 45°.<br />

Given that the OD=6” Thickness=3/4”<br />

Answer:<br />

(a)<br />

The maximum shear wave angle ϴ = Sin -1 (ID/OD) = Sin -1 (2.25/3)<br />

ϴ = 48.6° Max.<br />

(b) ?

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