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A history of Greek mathematics - Wilbourhall.org

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curve in E 1<br />

, R<br />

THE QUADRATURE OF THE PARABOLA 87<br />

2<br />

, ... . Join<br />

F, QB 2<br />

meeting<br />

l<br />

E l<br />

in F lt<br />

and so on.<br />

QR X<br />

,<br />

and produce it to meet OE in<br />

o Ht h 2 h 3 Hy, a<br />

Now Archimedes has proved in a series <strong>of</strong> propositions<br />

(6-13) that, if a trapezium such as<br />

1<br />

E 1<br />

E 2 2<br />

is suspended<br />

from H X<br />

H 2<br />

,<br />

and<br />

so suspended, it<br />

an area P suspended at J. balances 1E 1<br />

E 2 2<br />

will take a greater area than P suspended at<br />

A to balance the same trapezium suspended from H 2<br />

and<br />

a less area than P to balance the same trapezium suspended<br />

from H .<br />

1<br />

A similar proposition holds with regard to a triangle<br />

such as E n<br />

H n Q suspended where it is and suspended at Q and<br />

H n respectively.<br />

Suppose (Props. 14, 15) the triangle QqE suspended where<br />

it is from OQ, and suppose that the trapezium E0 lt<br />

suspended<br />

where it is, is balanced by an area F^ suspended at A, the<br />

trapezium suspended where El 2 it is, is balanced by P , 2<br />

suspended at A, and so on, and finally the triangle E n O n Q,<br />

suspended where it is, is balanced by P n+1 suspended at A<br />

;<br />

then P Y<br />

+ P 2<br />

+ ... +P n+1 at A balances the whole triangle, so that<br />

P 1<br />

+ P 2<br />

+... + P n+l<br />

= iA_E q Q,<br />

since the whole triangle may be regarded as suspended from<br />

the point on OQ vertically above its centre <strong>of</strong> gravity.<br />

Now AO:OH<br />

l<br />

= QO:OH l<br />

= Qq:q0 1<br />

= E^O^O^, by Prop. 5,<br />

= (trapezium EO^) : (trapezium<br />

P0 2 ),

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